Te question is missing some information. However, I'll try to help you out with the steps.
We have the relation between velocity, wavelength and frequency expressed as follows:
c = λμ
where:
c is the speed of the wave
λ is the wavelength of the wave
μ is the frequency of the wave
Substituting in the above equation, we can get the frequency of the wave which is the number of vibrations per units of time
We can then get the periodic time which is 1/frequency
Hope this helps :)
speed of the car = 45 m/s
distance traveled by the car = 2.5 km
here we know that
1 km = 1000 m
so we will have
distance = 2500 m
now in order to find out the time of motion we will have



so it will take 55.55 seconds
Explanation:
Metallic bonds hold metal atoms and freely moving valence electrons together, while Van der Waals forces hold nonpolar molecules together. OD. Metallic bonds hold metal atoms and freely moving valence electrons together while Van der Waals forces hold atoms together when they share valence electrons.
Frequency of the wave is 2 per second
Explanation:
- Frequency is the number of times waves pass at a particular point of time. Here, given time period = 3 s and number of waves that pass in 3 seconds = 6. Find the frequency of the wave per second.
- Frequency is given by the formula
f = 1/T, where f is the frequency and T is the time period
- For 3 seconds, frequency is 6
3 seconds ⇒ 6 waves
⇒ 1 second = 6/3 = 2 waves per second
#4). The concepts are: A). acceleration is always in the direction of the force, and B). friction always acts in the direction opposite to motion. (that's B)
#5). The concepts are: A). the NET force is the sum of all the individual forces acting (on this car, it's 1600N forward). and B). Force = (mass) x (acceleration). So Acceleration = (force) / (mass). For this car, that's (1600N forward) / (800 kg) .
#6). The concept is: As long as you don't exceed the "proportionality limit" of a spring, its extension is proportional to the load on it. That means that the change in extension is always proportional to the change in the load. So now, look at the table: As long as the load is 10N or less, the spring stretched 3cm longer for every 2N more of load. But if the load is somewhere between 10N and 12N, that relationship disappears. Something changes between 10N and 12N of load. The spring's "elastic limit" is somewhere in that slot.