Answer:
2.5 x 10⁻⁹ m
Explanation:
E = Energy of photon = 500 eV = 500 x 1.6 x 10⁻¹⁹ J
c = speed of photon = 3 x 10⁸ m/s
λ = wavelength of photon = ?
Energy of photon is given as

inserting the values

λ = 2.5 x 10⁻⁹ m
Answer:
no poop comes out from your but
Explanation:
To solve this problem, it is necessary to apply the concepts related to force described in Newton's second law, so that
F = ma
Where,
m = mass
a = Acceleration (Gravitational acceleration when there is action over the object of the earth)
Torque, as we know, is the force applied at a certain distance, that is,

Where
F= Force
d = Distance
Our values are given as,



Since the system is in equilibrium the difference of the torques is the result of the total Torque applied, that is to say






Therefore the magnitude of the frictional torque at the axle of the pulley if the system remains at rest when the balls are released is 
Answer:
V = 10581.59 V
Explanation:
To solve this problem, we have to take into the relation between the kinetic energy of an electron and the energy generated by the potential difference of an electric field. This relation is given by


where m is the mass of the electron, v is the velocity of the electron, e is the electric charge and V is the potential difference that accelerated the electron.
By taking V from the last expression we have:

where we have taken that
me = 9.1*10^(-31) Kg
e = -1.6*10^(-19) C
v = 6.1*10^(7)
I hope this is useful for you
Regards