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2 years ago

EXPERIMENT 1: How do you expect your coarse titration volume at the color change to compare to your fine titration volumes?

1 answer:

6 0

In the endpoint when the indicator changes color it gives the information that the acid is neutralized by the base.

<h3>What is Titration ? </h3>

Titration is also known as titrimetry is a technique where a solution of known concentration is used to calculate the concentration of the unknown solution. Titration is a laboratory technique.

<h3 /><h3>What is Endpoint ? </h3>

The point at which the indicator changes the color is known as Endpoint.

Thus from the above conclusion we can say that In the endpoint when the indicator changes color it gives the information that the acid is neutralized by the base.

Learn more about the Titration here: brainly.com/question/186765

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2 AgNO3(aq) + CaCl2(aq) -----> 2 AgCl(s) + Ca(NO3)2(aq)

yan [13]

5.732 grams of AgCl is formed when 0.200 L of 0.200 M AGNO3 reacts with an excess of CaCl2.

Explanation:

The balanced equation:

2 AgNO3(aq) + CaCl2(aq) -----> 2 AgCl(s) + Ca(NO3)2(aq)

data given:

volume of AgNO3 = 0.2 L

molarity of AgNO3 = 0.200 M

atomic weight of AgCl= 143.32 gram/mole

from the formula, number of moles can be calculated

Molarity = $\frac{number of moles}{volume in litres}$

number of moles of AgNO3 = 0.04

From the reaction:

2 moles of AgNO3 reacts to form 2 moles of AgCl

0.04 moles of AgNO3 reacts to form x mole of AgCl

$\frac{2}{2}$ = $\frac{x}{0.04}$

= 0.04 moles of AgCl is formed

mass of AgCl formed is calculated by multiplying number of moles with atomic mass of AgCl

mass of AgCl = 0.04 x 143.32

= 5.732 grams of AgCl is formed.

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