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4 years ago

Is it true or false?

Chemistry

1 answer:

svet-max [94.6K]4 years ago

6 0

False. It can’t because a glaciers weight combined with its gradual movement can drastically reshape the landscape over hundreds and even thousands of years.

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The pressure of 1 mol of gas is decreased to 0.5 atm at 273 K. What happens to the molar volume of the gas under these condition

m_a_m_a [10]

Answer : The molar volume of the gas will be, 44.82 L

Solution :

Using ideal gas equation,

$PV=nRT$

where,

n = number of moles of gas = 1 mole

P = pressure of the gas = 0.5 atm

T = temperature of the gas = 273 K

R = gas constant = 0.0821 Latm/moleK

V = volume of the gas.

Now put all the given values in the above equation, we get the molar volume of the gas.

$(0.5atm)\times V=(1mole)\times (0.0821Latm/moleK)\times (273K)$

$V=44.82L$

Therefore, the molar volume of the gas will be, 44.82 L

6 0

3 years ago

Which of the following statements is false?

jeka94

Answer:

a is write

Explanation:

Why are all ionic compounds crystalline in structure?

Ionic compounds are generally hard, but brittle. ... The repulsive forces between like-charged ions cause the crystal to shatter. When an ionic crystal breaks, it tends to do so along smooth planes because of the regular arrangement of the ions.

6 0

3 years ago

The Mole #2 Avogadro's Number PLEASE HELP ASAP! due tmr will give brainliest!

Elis [28]

The solution is here,

given mass of copper wire(m)=25 g

no. of moles in given mass of Cu=0.393

a) no. of atoms= no. of moles×avogardo's number

=0.393×6.023×10^23=2.36 ×10^23 atoms

b) 25 g of Cu wire has 0.393 moles

so 200 g of Cu wire has 0.393/25 × 200=3.144 mol.

no. of atoms= 3.144×2.023×10^23=1.89×10^24 atoms.

c) 25 g of Cu wire has 2.36×10^23 atoms

so 5 g of Cu wire has (2.36×10^23)/25 × 5

=4.72×10^22 atoms

( b can also be solve like c)

7 0

3 years ago

Calculate the specific heat capacity for a 22.7-g sample of lead that absorbs 237 J when its temperature increases from 29.8 °C

soldier1979 [14.2K]

Answer:

$\boxed {\boxed {\sf c\approx 0.159 \ J/ g \textdegree C}}$

Explanation:

We are asked to find the specific heat capacity of a sample of lead. The formula for calculating the specific heat capacity is:

$c= \frac{Q}{m \times \Delta T}$

The heat absorbed (Q) is 237 Joules. The mass of the lead sample (m) is 22.7 grams. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature. The temperature increases from 29.8 °C to 95.6 °C.

ΔT = final temperature -inital temperature
ΔT= 95.6 °C - 29.8 °C = 65.8 °C

Now we know all three variables and can substitute them into the formula.

Q= 237 J
m= 22.7 g
ΔT = 65.8 °C

$c= \frac {237 \ J}{22.7 \ g \ \times \ 65.8 \textdegree C}$

Solve the denominator.

22.7 g * 65.8 °C = 1493.66 g °C

$c= \frac {237 \ J}{1493.66 \ g \textdegree C}$

Divide.

$c= 0.1586706479 J /g \textdegree C$

The original values of heat, temperature, and mass all have 3 significant figures, so our answer must have the same. For the number we found that is the thousandth place. The 6 in the ten-thousandth place tells us to round the 8 up to a 9.

$c \approx 0.159 \ J/g \textdegree C$

The specific heat capacity of lead is approximately 0.159 Joules per gram degree Celsius.

3 0

3 years ago

What is the chemical name for LiC2H3O2 or C2H3O2Li

bixtya [17]

Answer:

AWAWDWDAD

Explanation:

3 0

3 years ago