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iris [78.8K]
3 years ago
5

If your mixing cement for the foundation of a building and it calls for 1.55 tons of sand, how many grams of a sand are you usin

g? Please show your work, and report your answer with the correct number of significant figures and appropriate units.
Chemistry
1 answer:
Damm [24]3 years ago
6 0

Answer:

1406136 grams

Explanation:

You might be interested in
How many moles of sodium bicarbonate are in 1.50 kg of the compound?
salantis [7]

Answer:

n=17.85 moles

Explanation:

Given mass is, m = 1.5 kg = 1500 g

The molar mass of sodium bicarbonate is, M = 84.007 g/mol

We need to find the no of moles in 1.5 kg of Sodium bicarbonate . We know that, no of moles is equal to given mass divided by molar mass.

n=\dfrac{m}{M}\\\\n=\dfrac{1500}{84.007 }\\\\n=17.85

<h2>So, there are 17.85 moles in 1.5 kg of Sodium bicarbonate.</h2>
3 0
3 years ago
Help, and fast! I really need an answer to this.
Travka [436]

Answer:

Explanation:says these bars are like co vid i get em right off teh bat

8 0
3 years ago
What is the color of the indicator thymol blue in a solution that has a ph of 11?.
Leviafan [203]

Answer:

Red

Explanation:

Red color is evidenced when thymol blue indicator is in a solution having a pH of 11. A pH of 11 means that the solution is basic or alkaline. Therefore, the indicator turns red, indicating that the solution is alkaline.

When thymol blue indicator is in a acidic solution, the indicator remains blue.

8 0
2 years ago
A 48.0g sample of quartz, which has a specific heat capacity of 0.730·J·g−1°C−1, is dropped into an insulated container containi
Butoxors [25]

Answer:

The equilibrium temperature of the water is 26.7 °C

Explanation:

<u>Step 1:</u> Data given

Mass of the sample quartz = 48.0 grams

Specific heat capacity of the sample = 0.730 J/g°C

Initial temperature of the sample = 88.6°C

Mass of the water = 300.0 grams

Initial temperature = 25.0°C

Specific heat capacity of water = 4.184 J/g°C

<u>Step 2:</u> Calculate final temperature

Qlost = -Qgained

Qquartz = - Qwater

Q =m*c*ΔT

Q = m(quartz)*c(quartz)*ΔT(quartz) = -m(water) * c(water) * ΔT(water)

⇒ mass of the quartz = 48.0 grams

⇒ c(quartz) = the specific heat capacity of quartz = 0.730 J/g°C

⇒ ΔT(quartz) = The change of temperature of the sample = T2 -88.6 °C

⇒ mass of water = 300.0 grams

⇒c(water) = the specific heat capacity of water = 4.184 J/g°C

⇒ ΔT= (water) = the change in temperature of water = T2 - 25.0°C

48.0 * 0.730 * (T2-88.6) -300.0 * 4.184 *(T2 - 25.0)

35.04(T2-88.6) = -1255.2 (T2-25)

35.04T2 -3104.544 = -1255.2T2 + 31380

1290.24T2 = 34484.544

T2 = 26.7 °C

The equilibrium temperature of the water is 26.7 °C

8 0
2 years ago
I need help with this
Lelechka [254]

Answer:

The answer is its equal to the volume of its container.

--------------------------------------------------------------------------------

I hope this helps! :)

7 0
3 years ago
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