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iris [78.8K]
3 years ago
5

If your mixing cement for the foundation of a building and it calls for 1.55 tons of sand, how many grams of a sand are you usin

g? Please show your work, and report your answer with the correct number of significant figures and appropriate units.
Chemistry
1 answer:
Damm [24]3 years ago
6 0

Answer:

1406136 grams

Explanation:

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The sanlinity of ocean water
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35g/l

Explanation:

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4 0
3 years ago
How many grams of K2CO3 are needed to prepare a 400.0 mL of a 4.25M solution?
Basile [38]

Answer:

235 g

Explanation:

From the question;

  • Volume is 400.0 mL
  • Molarity of a solution is 4.25 M

We need to determine the mass of the solute K₂CO₃,

we know that;

Molarity = Number of moles ÷ Volume

Therefore;

First we determine the number of moles of the solute;

Moles = Molarity × volume

Moles of  K₂CO₃ = 4.25 M × 0.4 L

                           = 1.7 moles

Secondly, we determine the mass of  K₂CO₃,

We know that;

Mass = Moles × Molar mass

Molar mass of  K₂CO₃, is 138.205 g/mol

Therefore;

Mass = 1.7 moles × 138.205 g/mol

         = 234.9485 g  

         = 235 g

Thus, the mass of  K₂CO₃ needed is 235 g

7 0
4 years ago
The saturation point for a solution is 45.0 grams of solute per 500 grams of solvent. If you pour 50.0 grams of
zheka24 [161]

Answer:

5.00 g  of solute  will remain undissolved at the bottom of the container

Explanation:

From the question, the solubility of the solute in the given solvent is 45.0 grams of solute per 500 grams of solvent.

Now if i pour 50.0 grams of  solute into 800 grams of solvent, it means that only 45 g will dissolve in 500 g of solvent leaving the additional 5 g undissolved.

Hence, 5 g  of solute  will remain undissolved at the bottom of the container.

3 0
3 years ago
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