Its in vertical columns. I hope this helps and you get a 100 on your test!
3.2 x 3.2 x 3.2 x 3.2 = 104.8576
Using the equation PV = nRT
Therefore; V = nRT / P
Need moles of glucose converted to moles of the product gas (CO2).
Molecular weight calculation:
C 6 X 12.01 = 72.06
H 12 X 1.01= 12.12
O 6 X 16.00 = 96.00
sum = 180.18
25.5 g of C6H12O6 ( 1 mol C6H12O6 / 180.18 g) ( 6 mol CO2 / 1 mol C6H12O6) =
0.84915 mol CO2 gas.
Convert temp: 37 °C + 273.15 = 310.15 K
V= ((0.84915 mol)× (0.0821 L atm / mol K) (310.15 K))/0.980 atm
V = 22.0635 L
= 22.06 L CO2
Answer:
The answer to your question is:
Explanation:
1) Data
mass = 10 g
vol = 20 ml
density = 10/ 20
= 0.5 g/ml
2)
Data
mass = 5 g
density = 2 g/ml
volume = mass / density
= 5 g / 2
= 2.5 g / ml
3)
Data
density = 25 g/ml
volume = 100 ml
mass = 25 x 100
= 2500 g
Answer:
Water Solubility Test
Explanation:
Ethanol possess a polar -OH group which is capable of forming hydrogen bond in water. Thus making ethanol miscible with water and ultimately soluble.
Cyclohexane on the other hand is a non polar compound with no dipole-dipole interaction ability with water. This makes it insoluble in water