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Naddika [18.5K]
1 year ago
9

During long jump athlete runs before taking the jump by doing so he

Physics
1 answer:
Alenkasestr [34]1 year ago
5 0

A. During long jump athlete runs before taking the jump by doing so he provides himself a larger inertia.

<h3>What is inertia?</h3>

Inertia is the reluctance of an object to stop moving once in motion or start moving when it is at rest.

When an athlete runs before taking the jump, he is trying to increase his inertia, that is his reluctance to stop, thereby increasing his forward motion or jump.

Thus, during long jump athlete runs before taking the jump by doing so he provides himself a larger inertia.

Learn more about inertia here: brainly.com/question/1140505

#SPJ1

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vovangra [49]

Answer:

Explanation:

electric field at the location of electron

= 9 x 10⁹ x 7.2 / .03²

= 72 x 10¹² N/C

force on electron = electric field x charge on electron

= 72 x 10¹² x 1.6 x 10⁻¹⁹

= 115.2 x 10⁻⁷ N .

C )

work done = charge on electron x potential difference at two points

potential at .03 m

= 9 x 10⁹ x 7.2 / .03

= 2.16 x 10¹² V

potential at .001 m

= 9 x 10⁹ x 7.2 / .001

= 64.8 x 10¹² V

potential difference = (64.8 - 2.16 )x 10¹² V

= 62.64 x 10¹² V  .

work done = 62.64 x 10¹² x 1.6 x 10⁻¹⁹

= 100.224 x 10⁻⁷ J .

D )

There will be no change in the magnitude of force on positron except that the direction of force will be reversed . In case of electron , there will be repulsion and in case of positron , there will be attraction .

Work done in case of electron will be positive and work done in case of positron will be negative .

electric field due to charge will be same in both the cases .

8 0
3 years ago
The mass of the skier including his equipment is 75 kg in the ski race, the total vertical change in height is 880m
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3 years ago
An occupant of a car has a chance of surviving a crash if the deceleration during the crash is not more then 30 g. Calculate the
sweet [91]

Answer:

20,850 N

Explanation:

We can solve the problem by using second Newton's Law:

F=ma

where

F is the force

m is the mass

a is the acceleration

In this problem, we have:

m = 70 kg is the mass

a=-30 g=-30 (9.8 m/s^2)=-294 m/s^2 is the acceleration (which is negative, because it is a deceleration)

So, we can use the equation above to find the force:

F=(70 kg)(-294 m/s^2)=-20580 N

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5 0
3 years ago
Two identical twins hold on to a rope, one at each end, on a smooth, frictionless ice surface. They skate in a circle about the
777dan777 [17]

Answer:

Part a)

L = 2683.2 kg m^2/s

Part b)

v' = 8.60 m/s

Part c)

W = 4326.7 J

Explanation:

Part a)

As we know that there is no external torque on the system of two twins

so here we will use

L = mv r + mvr

L = 2(78 \times 4.30 \times 4)

L = 2683.2 kg m^2/s

Part b)

Since angular momentum is conserved here as there is no external torque

so we will have

2(m v r) = 2( m v' \frac{r}{2})

v' = 2v

v' = 8.60 m/s

Part c)

Work done by both of them = change in kinetic energy

so we have

W = 2(\frac{1}{2}mv'^2 - \frac{1}{2}mv^2)

W = m(v'^2 - v^2)

W = 78(8.60^2 - 4.3^2)

W = 4326.7 J

5 0
3 years ago
Helpppp meeeee eee!! ​
jeka94

Answer: its a

Explanation: hope this help im sorry if its wrong

 

4 0
2 years ago
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