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4vir4ik [10]
3 years ago
12

Which of the following could describe the velocity of an object?

Physics
2 answers:
spin [16.1K]3 years ago
7 0

Answer:

Explanation:

50 ms east

tresset_1 [31]3 years ago
7 0
Yeah it is 50 ms east
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A 99.1-kg baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is μk =
Stels [109]

Answer:

628.022466 N

8.61 m/s

Explanation:

m = Mass

\mu = Coefficient of friction

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

F_f=\mu mg\\\Rightarrow F_f=0.646\times 99.1\times 9.81\\\Rightarrow F_f=628.022466\ N

Magnitude of frictional force is 628.022466 N

F=ma\\\Rightarrow a=\frac{F_f}{m}\\\Rightarrow a=\frac{628.022466}{99.1}\\\Rightarrow a=6.33726\ m/s^2

v=u+at\\\Rightarrow 0=u-6.33726\times 1.36\\\Rightarrow u=8.61\ m/s

Initial speed of the player is 8.61 m/s

4 0
3 years ago
A plucked violin string carries a traveling wave given by the equation f(x,t)=asin[b(x−ct)+ϕi], with a = 0.00580 m , b = 33.05 m
Viktor [21]

Answer:

A) Φ = 0 , B)  T = 7.76 s

Explanation:

A) to find the value of the phase constant replace the value

          0 = a sin (b (0- 0) + Φ)

           0 = sin Φ

           Φ = sin⁻¹ 0

           Φ = 0

B) the period is defined by time or when the movement begins to repeat itself

So that the sine function is repeated when the angle passes 2pi

            b (x- ct) = 2pi

If we are at a fixed point x = 0

           b c t = 2pi

            t = 2π / bc

Let's calculate

            T = 2π / (33.05 245)

            T = 7.76 s

0 0
3 years ago
Read 2 more answers
What happens when a proton is placed directly in the path of the proton cannon?
blondinia [14]

Answer:coherent light

Explanation:

5 0
3 years ago
A bullet with mass 1.0kg and velocity 180 m/s is brought to rest in 0.02 s by a sandbag.assuming constant acceleration in the sa
kotykmax [81]
Hello
The bullet is moving by uniformly accelerated motion.
The initial velocity is v_i=180~m/s, the final velocity is v_i=0~m/s, and the total time of the motion is \Delta t=0.02~s, so the acceleration is given by
a= \frac{v_f-v_i}{\Delta t} = -9000~m/s^2 
where the negative sign means that is a deceleration.
Therefore we can calculate the total distance covered by the bullet in its motion using
S=v_i t + \frac{1}{2}at^2 = 180~m/s \cdot 0.02~s + \frac{1}{2}(-9000~m/s^2)(0.02~s)^2=1.8~m
So, the bullet penetrates the sandbag 1.8 meters.
5 0
3 years ago
Someone please helppp :|||
juin [17]

Answer:

b

Explanation:

4 0
3 years ago
Read 2 more answers
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