Answer:
The ball will be at 700 m above the ground.
Explanation:
We can use the following kinematic equation
.
where y(t) represent the height from the ground. For our problem, the initial height will be:
.
The initial velocity:
,
take into consideration the minus sign, that appears cause the ball its thrown down. The same minus appears for the acceleration:
![a=-10\frac{m}{s}](https://tex.z-dn.net/?f=a%3D-10%5Cfrac%7Bm%7D%7Bs%7D)
So, the equation for our problem its:
.
Taking t=6 s:
.
.
.
.
.
So this its the height of the ball 6 seconds after being thrown.
Answer:
Vmax=11.53 m/s
Explanation:
from conservation of energy
![E_A} =E_{B}](https://tex.z-dn.net/?f=E_A%7D%20%3DE_%7BB%7D)
Spring potential energy =potential energy due to elevation
0.5*k*x²= mg
=mgh
0.5*k*2.3²= 430*9.81*6
k=9568.92 N/m
For safety reason
k"=1.13 *k= 1.13*9568.92
k"=10812.88 N/m
agsin from conservation of energy
![E_A} =E_{C}](https://tex.z-dn.net/?f=E_A%7D%20%3DE_%7BC%7D)
spring potential energy=change in kinetic energy
0.5*k"*x²=0.5*m*![V_{max}^{2}](https://tex.z-dn.net/?f=V_%7Bmax%7D%5E%7B2%7D)
10812.88 *2.3²=430*![V_{max}^{2}](https://tex.z-dn.net/?f=V_%7Bmax%7D%5E%7B2%7D)
=11.53 m/s
Answer:
The value is ![N =36203 \ turns](https://tex.z-dn.net/?f=N%20%3D36203%20%5C%20%20turns)
Explanation:
From the question we are told that
The length of the solenoid is ![l = 0.56 \ m](https://tex.z-dn.net/?f=l%20%3D%200.56%20%5C%20%20m)
The magnetic field is ![B = 6.5 \ T](https://tex.z-dn.net/?f=B%20%20%3D%20%206.5%20%5C%20T)
The current is ![I = 80 \ A](https://tex.z-dn.net/?f=I%20%3D%2080%20%5C%20A)
The desired temperature is ![T = 4.2 \ K](https://tex.z-dn.net/?f=T%20%3D%204.2%20%5C%20K)
Generally the magnetic field is mathematically represented as
![B = \frac{\mu_o * N * I }{L }](https://tex.z-dn.net/?f=B%20%20%3D%20%5Cfrac%7B%5Cmu_o%20%2A%20N%20%2A%20I%20%7D%7BL%20%7D)
=> ![N = \frac{B * L }{\mu_o * I }](https://tex.z-dn.net/?f=N%20%3D%20%5Cfrac%7BB%20%20%2A%20L%20%7D%7B%5Cmu_o%20%2A%20I%20%7D)
Here
is the permeability of free space with value
![\mu_o = 4\pi * 10^{-7} N/A^2](https://tex.z-dn.net/?f=%5Cmu_o%20%3D%20%204%5Cpi%20%2A%2010%5E%7B-7%7D%20N%2FA%5E2)
So
![N = \frac{6.5 * 0.56 }{ 4\pi * 10^{-7} * 80 }](https://tex.z-dn.net/?f=N%20%3D%20%5Cfrac%7B6.5%20%20%2A%200.56%20%7D%7B%204%5Cpi%20%2A%2010%5E%7B-7%7D%20%2A%20%2080%20%20%7D)
=> ![N =36203 \ turns](https://tex.z-dn.net/?f=N%20%3D36203%20%5C%20%20turns)
Answer:
Action - Pulling up the train.
Reaction - Friction on the locomotive
Explanation:
Locomotive is pulling the train upwards ,
Which is the action force applied by the locomotive,
As a reaction locomotive will be pulled by the train which is the reaction of pulling
Now, considering it as a action on locomotive , friction force will act on it as a reaction upwards which will result to move it upwards.
For train action is pulling up by locomotive and reaction will be friction acting on it downwards.
Your teacher is right. The moon can be seen early in the morning sometimes and late at night. Different phases are only visible on certain days as one day might be full quarter, the next full moon, the next first quarter, etc.