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3 years ago

Which statement best describes an atom? (2 points)

Physics

2 answers:

alekssr [168]3 years ago

7 0

Answer:

A group of protons and neutrons that are surrounded by electrons I think that's the answer...

Explanation:

andre [41]3 years ago

5 0

^ what they said
explanation: i don’t remember

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Two identical traveling waves, moving in the same direction, are out of phase by π/5.0 rad. What is the amplitude of the resulta

andreev551 [17]

Answer:

Therefore the amplitude of the resultant wave is $=0.95 y_m$

Explanation:

The equation of wave:

y=A sin (kx-ωt)

For wave 1:

y₁=A sin (kx-ωt) = $y_{m}$ sin (kx-ωt)

For wave 2:

y₂=A sin (kx-ωt+Φ) = $y_{m}$ sin (kx-ωt+Φ)

Where A= amplitude= $y_m$

The angular frequency $\omega=\frac{2\pi}{T}$

$k=\frac{2\pi}{\lambda}$ , $\lambda$ = wave length.

t= time

T= Time period

$\phi$ = phase difference = $\frac{\pi}{5}$

The resultant wave will be

y = y₁ + y₂

= $y_m$ sin (kx-ωt) + $y_m$ sin (kx-ωt+Φ)

$=y_m$ {sin (kx-ωt) + sin (kx-ωt+Φ)}

$=y_m\ sin(\frac{kx-\omega t +\phi + kx-\omega t }2)\ cos(\frac{kx-\omega t +\phi -kx+\omega t}2)$

$=y_m\ sin({kx-\omega t +\frac\phi 2)\ cos(\frac{\phi }2)$

$=y_m\ cos(\frac{\phi }2) sin({kx-\omega t +\frac\phi 2)$

Therefore the amplitude of the resultant wave is

$=y_m\ cos(\frac{\phi }2)$

$=y_m\ cos(\frac{\pi }{10})$

$=0.95 y_m$

6 0

4 years ago

A sun-like star is barely visible to naked-eye observers on earth when it is a distance of 7.0 light years, or 6.6 * 1016 m, awa

igomit [66]

Answer:

At a distance of 1376.49 candle emits 0.2 watt power

Explanation:

Distance between Sun and earth $6.6\times 10^{16}m$

Sun emits a power of $P=3.8\times 10^{26}watt$

Power emitted by candle = 0.20 watt

We know that brightness is given by

$B=\frac{P}{4\pi d^2}$

So $\frac{3.8\times 10^{26}}{4\pi (6\times 10^{16})^2}=\frac{0.20}{4\pi d^2}$

$3.8\times 10^{26}d^2=7.2\times 10^{32}$

$d^2=1.89\times 10^6$

$d=1376.49m$

So at a distance of 1376.49 candle emits 0.2 watt power

3 0

3 years ago

Find the average net force.

Lerok [7]

Answer:

<h2>given</h2>

mass= 3.5 kg

distance covered= 0.4m

inital speed = 1.5 m/sec

final speed = 0 m/sec

net force

<h2>solution</h2>

formula for force :

$\fbox{f = m.a}$

In order to find the force we need to find the acceleration.

According to third equation of Kinematics-

$\bold{ {v}^{2} = {u}^{2} + 2as}$

where,

v= final velocity

u=inital Velocity

a=Acceleration

s=Distance covered

put the value in the above equation

0= (1.5)²+ 2a x 0.4

-2.25= 0.8a

a = -2.25/0.8

a= - 2.8125 m/sec²

now put the value 0f accleration in formula of force

F = 3.5 x - 2.8125

F= -9.84375 N

6 0

3 years ago

A fixed mass of an ideal gas has a volume of 800 cm3 under certain conditions. The pressure (in kPa) and temperature (in K) are

Mashutka [201]

Answer:

800cm3

Explanation:

This is a general gas law question

Which has the relationship P1V1/T1 = P2V2/T2

P1= P1 in kPa

T1 = T1 in K

V1= 800cm3

V2=?

P2= 2* P1

T2= 2*T1

The volume of gas after the changes (V2), making it as the subject of formula

V2= P1*V1*T2/P2*T1

V2 = P1 *800* 2T1 / 2P1 * T1 ; dividing accordingly, we have

V2 = 800cm3

3 0

4 years ago

If the positive charge of an atoms nucleus exactly balances the negative charge of the surrounding electrons the atom is_______

VARVARA [1.3K]

The answer is A. Neutral.

7 0

3 years ago

Read 2 more answers