Question

A second rock is thrown straight upward with a speed 4.750 m/s . If this rock takes 2.006 s to fall to the ground, from what height H was it released?

Answer 1

Answer:

29.23 meters

Explanation:

H = ut + 1/2gt^2

Initial velocity u = 4.750m/s

time t = 2.006 secs

Acceleration due to gravity g = 9.8m/s^2

H =

4.750 x 2.006 + 1/2 x 9.8 x (2.006)^2

9.53 + 1/2 x 9.8 x 4.02

9.53 + 39.396/2

9.53 + 19.698

29.23 meters