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Nina [5.8K]
3 years ago
5

A second rock is thrown straight upward with a speed 4.750 m/s . If this rock takes 2.006 s to fall to the ground, from what hei

ght H was it released?
Physics
1 answer:
Naddika [18.5K]3 years ago
8 0

Answer:

29.23 meters

Explanation:

H = ut + 1/2gt^2

Initial velocity u = 4.750m/s

time t = 2.006 secs

Acceleration due to gravity g = 9.8m/s^2

H =

4.750 x 2.006 + 1/2 x 9.8 x (2.006)^2

9.53 + 1/2 x 9.8 x 4.02

9.53 + 39.396/2

9.53 + 19.698

29.23 meters

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r-ruslan [8.4K]

\huge\bold{\purple{\bold{⚡A. Energy⚡}}}

\huge\underline\mathtt\colorbox{cyan}{Reason:}

When a force causes a body to move, work is done on the object by the force. Work is the measure of the energy transfer when a force 'F' moves an object through a distance 'd'. So we say that energy is transferred from one energy store to another when work is done, and therefore, energy transferred = work done.

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3 years ago
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Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 403 km above the earth’s sur
BARSIC [14]

Answer:

v_A=7667m/s\\\\v_B=7487m/s

Explanation:

The gravitational force exerted on the satellites is given by the Newton's Law of Universal Gravitation:

F_g=\frac{GMm}{R^{2} }

Where M is the mass of the earth, m is the mass of a satellite, R the radius of its orbit and G is the gravitational constant.

Also, we know that the centripetal force of an object describing a circular motion is given by:

F_c=m\frac{v^{2}}{R}

Where m is the mass of the object, v is its speed and R is its distance to the center of the circle.

Then, since the gravitational force is the centripetal force in this case, we can equalize the two expressions and solve for v:

\frac{GMm}{R^2}=m\frac{v^2}{R}\\ \\\implies v=\sqrt{\frac{GM}{R}}

Finally, we plug in the values for G (6.67*10^-11Nm^2/kg^2), M (5.97*10^24kg) and R for each satellite. Take in account that R is the radius of the orbit, not the distance to the planet's surface. So R_A=6774km=6.774*10^6m and R_B=7103km=7.103*10^6m (Since R_{earth}=6371km). Then, we get:

v_A=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{6.774*10^6m} }=7667m/s\\\\v_B=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{7.103*10^6m} }=7487m/s

In words, the orbital speed for satellite A is 7667m/s (a) and for satellite B is 7487m/s (b).

7 0
3 years ago
What is the answer of A and B question 2
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cestrela7 [59]

Answer:

answer is A

Explanation:

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28. Ken and Musa shared a cake such that Ken got twice the size
ratelena [41]

Answer:

Musa = \frac{1}{3}

Ken = \frac{2}{3}

Explanation:

Given

Ken = 2 * Musa --- Ken's share

Required

The fraction each got

Since they both shared a cake, we have:

Ken + Musa = 1

Substitute: Ken = 2 * Musa

2 * Musa+ Musa = 1

Factorize

Musa(2+ 1)= 1

Musa(3)= 1

Divide both sides by 3

Musa = \frac{1}{3}

Recall that: Ken = 2 * Musa

Ken = 2 * \frac{1}{3}

Ken = \frac{2}{3}

3 0
3 years ago
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