Answer:
0.15A
Explanation:
The parameters given are;
R=20.0 Ω
C= 2.50 μF
V= 3.00 V
f= 2.48×10^-3 Hz
Xc= 1/2πFc
Xc= 1/2×3.142 × 2.48×10^-3 × 2.5 ×10^-6
Xc= 25666824.1
Z= 1/√(1/R)^2 +(1/Xc)^2
Z= 1/√[(1/20)^2 +(1/25666824.1)^2]
Z= 1/√(2.5×10^-3) + (1.5×10^-15)
Z= 20 Ω
But
V=IZ
Where;
V= voltage
I= current
Z= impedance
I= V/Z
I= 3.00/20
I= 0.15A
Thank you for posting your questions here at brainly. Beginning at the corner of the floor where the lamp is standing, the dog's head is at a point which is -- 6 feet along the wall towards the kitchen door -- 4 <span>feet across the room towards the garage -- 2 feet up off the floor</span>
Answer:
Yes, it would work.
Explanation:
From Flehmings left hand rule, current can be generated when a coil cuts the magnetic field of a powerful magnet. Thus, the spin of properller turns a generator thereby converts motion to electrical energy.
The major challenge would be how to set the car in motion when at rest. But this can be solved by energy consrvation process. The law of conservation of energy states that energy cannot be created or destoyed, but transformed from one form to another. Thus, there would be mechanism having a device called an inverter which stores electric energy when the vehicle is in motion. This regenerates the required initial energy to set the electric car in motion when at rest or stops.
Answer:
The light bends away from the normal
Explanation:
We can solve the problem by using Snell's law:
where:
is the index of refraction of the first medium
is the index of refraction of the second medium
is the angle of incidence (angle between the incoming ray and the normal to the interface)
is the angle of refraction (angle between the outcoming ray and the normal to the interface)
We can rearrange the equation as
In this problem, light travels from an optically denser medium to an optically rarer medium, so
Therefore, the term 
is greater than 1, so
which means that the angle of refraction is greater than the angle of incidence, and so the light will bend away from the normal.
The basic relationship between the frequency of a wave and its period is
where f is the frequency and T the period of vibration.
In our problem, the frequency is
so, by re-arranging the previous formula, we can find the period of the wave:
