1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
LenKa [72]
2 years ago
5

Ria surveyed 20 classmates to ask what types of pets they had at home. calculate the relative frequency of each pet type.

Mathematics
1 answer:
maksim [4K]2 years ago
4 0

The relative frequencies for all pets are given-

The relative frequency for dog is 0.4.

The relative frequency for cat is 0.35.

The relative frequency for bird is 0.15.

The relative frequency for fish is 0.1

<h3>What is relative frequency?</h3>

The ratio of the total number of events occurring in a scenario to the number of times an event occurs is known as relative frequency.

Relative Frequency = Subgroup frequency/ Total frequency.

Relative Frequency = f/ n.

where, f = total frequency

n = subgroup frequency

Calculation for the relative frequencies of the pet types:

(1) Relative frequency for dog:

Total frequency is 20.

The frequency for dog is 8.

Relative frequency for dog =  frequency for dog/total frequency

                                             = 8/20

                                             = 0.4

Relative frequency for dog = 0.4.

(2) Relative frequency for cat:

Total frequency is 20.

The frequency for cat is 7.

Relative frequency for cat =  frequency for cat/total frequency

                                             = 7/20

                                             = 0.35

Relative frequency for cat = 0.35.

(3) Relative frequency for bird:

Total frequency is 20.

The frequency for bird is 3.

Relative frequency for bird =  frequency for bird/total frequency

                                             = 3/20

Relative frequency for bird = 0.15.

(4) Relative frequency for fish:

Total frequency is 20.

The frequency for fish is 2.

Relative frequency for fish =  frequency for fish/total frequency

                                             = 2/20

Relative frequency for fish = 0.1.

To know more about relative frequency, here

brainly.com/question/3857836

#SPJ4

You might be interested in
Solve for x (2x-8) (9x-10)
mars1129 [50]

Answer

x+3=17

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Evaluate The diagram below.<br> Given: straight lines AD and CE.<br> HELP ASAP‼️‼️
jenyasd209 [6]

Answer:

<CFD =62°

<AFB= 90°

Step-by-step explanation:

here you have a vertical angle, so to simply put it the answer on one side of the angle is the same answer for the opposite side of the angle. knowing this, angle <AFE is 62° and <CFD is on the opposite side making the angle the same(62°). the opposite angle of <AFB is <EFD which is 118° but both <AFB and <AFC equal 118° so you subtract 118° to <AFC degree which is 28° and you get 90°.

i hope this makes sense im not good at explaining. if anyone has a better explanation feel free to correct me.

6 0
3 years ago
What are the factors of 21?
skelet666 [1.2K]
The answer will be 1,3,7
8 0
3 years ago
Which graph represents the function f(x)= 1/x - 1<br> PLEASE ANSWER FAST IM TIMED
marusya05 [52]
Number 3, because if you replace x for 1 then you get zero. and because it is rise over run then the run is 0. it is the only line with a run of 0

6 0
3 years ago
Read 2 more answers
Dogs are inbred for such desirable characteristics as blue eye color, but an unfortunate by-product of such inbreeding can be th
sesenic [268]

Answer:

The probability that the dogs are blue eyed and deaf is 13.02%.

Step-by-step explanation:

We are given the following information in the question:

P(Blue eyes) = 31%

P(Deaf) = 38%

P(Deaf | Blue eyes) = 42%

Formula for conditional probability:

P( A|B) = \displaystyle\frac{P(A \cap B)}{P(B)}

Now, let A be the event where the dog is deaf and B be the the event where dog is blue eyed.

P( \text{ Deaf}|\text{Blue eyes}) = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{P(\text{Blue eyes})}\\\\0.42 = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{0.31}\\\\P( \text{Deaf} \cap \text{Blue eyes}) = 0.42\times 0.31 = 0.1302 = 13.02\%

Hence, the probability that the dogs are blue eyed and deaf is 13.02%.

6 0
3 years ago
Other questions:
  • Which equation shows the quadratic formula used correctly to solve 5x2 + 3x – 4 = 0 for x?
    11·2 answers
  • I WILL GIVE BRAINLIEST please I really need the answer
    11·1 answer
  • NECESITO AYUDA EN ESTOS EJERCIICIOS DE MATES NIVEL SEGUNDO ESO
    11·1 answer
  • I really need help with this I don’t understand
    14·1 answer
  • WILL GIVE BRAINLIEST :)
    9·1 answer
  • Find the measure of each angle indicated. HELPPP PLEASE
    10·2 answers
  • I know the answer, but I just wanna know if the answer I got was right or wrong, if I'm wrong help down please
    7·1 answer
  • Which statement correctly describes gravity?
    14·2 answers
  • Find the value of x<br> 50<br> x
    15·1 answer
  • Which number is greater and by how much? a decreased by 50% and then increased by 50% of the result
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!