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Tpy6a [65]
2 years ago
5

In the diagram, the straight line ABC is parallel to EFG and DB is parallel to FC. Given that ABD=38 degrees and DFE=62 degrees.

Find angle BDF and CFG
Mathematics
1 answer:
Elanso [62]2 years ago
4 0

Based on the calculations, the measure of angle BDF and CFG are 100° and 38° respectively.

<h3>The condition for two parallel lines.</h3>

In Geometry, two (2) straight lines are considered to be parallel if their slopes are the same (equal) and they have different y-intercepts. This ultimately implies that, two (2) straight lines are parallel under the following conditions:

m₁ = m₂

<u>Note:</u> m is the slope.

<h3>What is the alternate interior angles theorem?</h3>

The alternate interior angles theorem states that when two (2) parallel lines are cut through by a transversal, the alternate interior angles that are formed are congruent.

Based on the alternate interior angles theorem, we can infer and logically deduce the following properties from the diagram (see attachment):

  • <ABD = <BDH = 38°
  • <DFE = <HDF = 62°

For angle BDF, we have:

<BDF = <BDH + <HDF

<BDF = 38° + 62°

<BDF = 100°.

Since angles BDF and DFC are linear pair, they are supplementary angles. Thus, we have:

∠BDF + <DFC = 180°

<DFC = 180 - ∠BDF

<DFC = 180 - 100

<DFC = 80°.

For angle CFG, we have:

∠DFE + <DFC + <CFG= 180°

<CFG = 180° - ∠DFE - <DFC

<CFG = 180° - 62° - 80°

<CFG = 38°.

Read more on parallel lines here: brainly.com/question/3851016

#SPJ1

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

A salesman who uses his car extensively finds that his gasoline bills average $125.32 per month with a standard deviation of $49.51.

This means that \mu = 125.32, \sigma = 49.51

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p-value of Z when X = 50. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{50 - 125.32}{49.51}

Z = -1.52

Z = -1.52 has a p-value of 0.0643

More than 150

1 subtracted by the p-value of Z when X = 150. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{150 - 125.32}{49.51}

Z = 0.5

Z = 0.5 has a p-value of 0.6915

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The probability that his bill will be less than $50 a month or more than $150 for a single month is:

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The probability that his bill will be less than $50 a month or more than $150 for a single month is 0.3728 = 37.28%.

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