X + (x+10)= -21
x^2 + 10x + 21 = 0
(x+7)(x+3)=0
x= -7 x= -3
Answer:
B. obtuse
Can't be right because 100 would have to = ab^2 + ac^2
to be acute, ab^2 + ac^2 would have to be greater than 100
Answer:
<em>y</em><em> </em><em>=</em><em> </em><em>5</em><em>7</em><em>°</em><em> </em><em>and</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>3</em><em>3</em><em>°</em>
Step-by-step explanation:
<em>I've</em><em> </em><em>attached</em><em> </em><em>a</em><em> </em><em>picture</em><em>.</em>
<em>:</em><em>)</em>
Answer:
(4,1)
Step-by-step explanation:
The vertex of the quadratic can be found using -b/2a. The vertex is the point (-b/2a, f(-b/2a)).
To find the x coordinate of the quadratic, define its a,b, and c. The quadratic has a = 2, b=-16, and c=31. Then -b/2a is -(-16)/2(2) = 16/4 = 4.
To find the y-coordinate, input the x=4 and solve for y.

The vertex is (4,1).