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Andrej [43]
2 years ago
13

Do the quantities combine?

Mathematics
1 answer:
Verdich [7]2 years ago
4 0

Answer:

D

Step-by-step explanation:

Widrawal is - 30

Deposit is +30

-30+30 = 0

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A map scale is 1:1000. what would 10cm represent in metres?​
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Answer:

10000 metres

Step-by-step explanation:

You calculate by multiplying the number of metres in the ratio by 10 centimetres.

Your answer should come out to 10000 (10:10000)

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Alther.† Suppose a small group of 15 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is
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Step-by-step explanation:

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3 years ago
Angles are not necessarily drawn to scale.<br><br> X=?
Tanzania [10]

Answer:

x = 76

Step-by-step explanation:

A line has an angle measurement of 180 degrees.

Knowing that, let's first find the angle measurement of DIJ:

180 - 107 = 73

Angle DIJ has an angle measurement of 73

To find the angle measurement of DJI, we have to apply knowledge of angles in a triangle. When you add all the angles in a triangle, they ALWAYS equal to 180 degrees.

Using that knowledge, we can add 73 and 31 and subtract that value from 180:

73 + 31 = 104

180 - 104 = 76

The angle measurement of Angle DJI is 76.

Because vertical angles are ALWAYS going to have the same angle measurement, Angle AJF is going to have an angle measurement of 76 as well.

So x = 76

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8 0
2 years ago
A university financial aid office polled a random sample of 670 male undergraduate students and 617 female undergraduate student
ahrayia [7]

Answer:

The 90% confidence interval for the difference between the proportions of male and female students who were employed during the summer is (0.01, 0.1012).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Male undergraduates:

670, 388 were employed. So

p_M = \frac{388}{670} = 0.5791

s_M = \sqrt{\frac{0.5791*0.4209}{670}} = 0.0191

Female undergraduates:

Of 617, 323 were employed. So

p_F = \frac{323}{617} = 0.5235

s_F = \sqrt{\frac{0.5235*0.4765}{617}} = 0.0201

Distribution of the difference:

p = p_M - p_F = 0.5791 - 0.5235 = 0.0556

s = sqrt{s_M^2+s_F^2} = \sqrt{0.0201^2 + 0.0191^2} = 0.0277

Confidence interval:

The confidence interval is given by:

p \pm zs

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower bound of the interval is:

p - zs = 0.0556 - 1.645*0.0277 = 0.01

The upper bound of the interval is:

p + zs = 0.0556 + 1.645*0.0277 = 0.1012

The 90% confidence interval for the difference between the proportions of male and female students who were employed during the summer is (0.01, 0.1012).

5 0
3 years ago
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