Find the shortest distance from A to B in the diagram below. A. 505‾‾‾‾√ m B. 17 m C. 329‾‾‾√ m D. 10 m
1 answer:
The shortest distance from A to B in the diagram is 17 m.
<h3>How to find the shortest distance?</h3>The shortest distance from D to B can be found as follows:
using Pythagoras theorem,
c² = a² + b²
where
- c is the hypotenuse
- a and b are the other legs
Therefore,
DB² = 15² + 8²
DB² = 225 + 64
DB² = 289
DB = √289
DB = 17 m
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The length of AC is 16 km.
Solution:
Given data:
AB = c = 14 km, ∠A = 30° and ∠B = 89°
AC = b = ?
<u>Let us first find angle C:</u>
<em>Sum of all angles in a triangle = 180°</em>
m∠A+ m∠B + m∠C = 180°
30° + 89° + m∠C = 180°
119° + m∠C = 180°
Subtract 119° from both sides, we get
m∠C = 61°
<u>To find the length of AC:</u>
<em>Using sine formula:</em>
Substitute the given values in the formula.
Multiply by sin 89° on both sides.
The length of AC is 16 km.
Answer:
A.
B.
C.