<h3>Answers are:
sine, tangent, cosecant, cotangent</h3>
Explanation:
On the unit circle we have some point (x,y) such that x = cos(theta) and y = sin(theta). The sine corresponds to the y coordinate of the point on the circle. Quadrant IV is below the x axis which explains why sine is negative here, since y < 0 here.
Since sine is negative, so is cosecant as this is the reciprocal of sine
csc = 1/sin
In quadrant IV, cosine is positive as x > 0 here. So the ratio tan = sin/cos is going to be negative. We have a negative over a positive when we divide.
Because tangent is negative, so is cotangent.
The only positive functions in Q4 are cosine and secant, which is because sec = 1/cos.
Answer:3y/(4y+6)-6y/(2y+3)
3y(2(2y+3))-6y/(2y+3)
(3y-6×2y)/(2(2y+3))
-9y/4y+6
1.st one is your answer. hope this helps
Hello I hope this helps. I'm pretty sure this is the answer.
Part A: C
Part B: A
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
3^5
3*3*3*3*3 = 243
3*3 = 9 *3=27 *3 =81 *3 =243