A molecule that contains delocalized electrons _______

Balance the following skeleton reaction and identify the oxidizing and reducing agents: Include the states of all reactants and

coldgirl [10]

Answer :

a. The oxidizing agent is: $BH_4^-$

b. The reducing agent is: $ClO_3^-$

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

$BH_4^-(aq)+ClO_3^-(aq)\rightarrow H_2BO_3^-(aq)+Cl^-(aq)$

The oxidation-reduction half reaction will be :

Oxidation : $BH_4^-\rightarrow H_2BO_3^-$

Reduction : $ClO_3^-\rightarrow Cl^-$

Now balance oxygen atom on both side.

Oxidation : $BH_4^-\rightarrow H_2BO_3^-+3H_2O$

Reduction : $ClO_3^-+3H_2O\rightarrow Cl^-$

Now balance hydrogen atom on both side.

Oxidation : $BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O$

Reduction : $ClO_3^-+3H_2O\rightarrow Cl^-+6OH^-$

Now balance the charge.

Oxidation : $BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O+4e^-$

Reduction : $ClO_3^-+3H_2O+6e^-\rightarrow Cl^-+6OH^-$

In order to balance the electrons, we multiply the oxidation reaction by 6 and reduction reaction by 4 and then added both equation, we get the balanced redox reaction.

Oxidation : $6BH_4^-+24OH^-\rightarrow 6H_2BO_3^-+18H_2O+24e^-$

Reduction : $4ClO_3^-+12H_2O+24e^-\rightarrow 4Cl^-+24OH^-$

The balanced chemical equation in acidic medium will be,

$6BH_4^-+4ClO_3^-\rightarrow 6H_2BO_3^-+6H_2O+4Cl^-$

$3BH_4^-+2ClO_3^-\rightarrow 3H_2BO_3^-+3H_2O+2Cl^-$

In the redox reaction, $ClO_3^-$ act as oxidizing agent and $BH_4^-$ act as an reducing agent.

7 0

3 years ago

Explain how stagnant sulfureted water may greatly accelerate metallic corrosion. (See the Email Link in Moodle) | (7 marks)

slavikrds [6]

Answer:

sulfur promotes oxide-reduction reactions.

Explanation:

In stagnant water, some solutes tend to precipitate. When Sulfur precipitate and touch a metal, Sulfur is being reduced and the metal is oxidated. This depends of potential redox of each element.

6 0

3 years ago

Determine the density of nh3 gas at 435k and 1.00atm

goldenfox [79]

We assume that this gas is ideal. Therefore, we can use the ideal gas equation which is expressed as:

PV=nRT

We manipulate this equation to give us an expression which will correspond to density. We do as follows:

PV= nRT
P/RT = n/V where n = m/MM
P(MM) /RT = m/V = density
Density = 1.00 (17.03) / 0.08206 (435)
Density = 0.48 g / L

5 0

4 years ago

What type(s) of atoms make up the element carbon?

ivolga24 [154]

A, as carbon is an atomic substance - element

8 0

3 years ago

Read 2 more answers

What stress will shift the following equilibrium system to the left? N2(g) + 3H2(g) ⇌ 2NH3(g)

oee [108]

<h3><u>Answer;</u></h3>

Decrease in pressure

<h3><u>Explanation;</u></h3>

If the pressure of a system is increased, the reaction will shift toward the side with fewer moles of gas, whereas when the pressure of a system is decreased, the reaction will shift toward the side with more moles of gas.
In this case; <em><u>If the pressure of the system with the above reaction decreases, the reaction will shift to the left. The reactants side has more moles of gas, so the reaction will shift toward the direction of the reactants.</u></em>

5 0

3 years ago

A molecule that contains delocalized electrons ________