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svlad2 [7]
2 years ago
10

An 80,000 kg plane is flying at 900 km/h at a height of 10 kilometers. What is its total mechanical energy? Group of answer choi

ces 478 MJ 250 MJ 10,340 MJ 773 MJ
Physics
1 answer:
Romashka-Z-Leto [24]2 years ago
4 0

The mechanical energy of the given flying object is 10,340 MJ. So the correct choice is 10,340 MJ.

Mechanical energy: The mechanical energy of an object is the sum of its potential energy and kinetic energy.

The formula for the mechanical energy E is:

E=K+U

where K is the kinetic energy and U is the potential energy.

Kinetic energy: The energy possessed by an object due to the motion.

The kinetic energy is given by the formula,

K=(1/2)*(mv^2)

where m is the mass of the object and v is the velocity of the object.

Potential energy: The energy possessed by an object due to its relative position from a given point.

The potential energy is given by the formula,

U=m*g*h

where g is the acceleration due to gravity and h is the height of the object from the ground.

Substitute K=(1/2)*(mv^2) and U=m*g*h in the formula of the mechanical energy to get the following formula,

E=(1/2)*(mv^2)+m*g*h

Given that m=80000 kg, h=10 km, and v=900 km/h, and the value of g is 9.8 m/s^(-2), the value of the total mechanical energy is,

E=(1/2)*(80,000 kg)(900 km/h )^2+(80,000 kg)*(9.8 m/s^(-2))*(10 km)

Note: 1 km= 1000 m and 1 km/h = 5/18 m/s. 1 MJ = 10^(6) J

E=(1/2)*(80,000 kg)*(900*(5/18) m/s )^2+(80000 kg)*(9.8 m/s^(-2))*(10000 m)

E=(1/2)*(80,000 kg)*(250 m/s)^2+7840*10^(6) J

E=2500*10^(6) J+7840*10^(6) J

E=10340*10^(6) J

E=10340 MJ

Learn more about Potential energy here:

brainly.com/question/15647581

#SPJ4

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At 4.00 l, an expandable vessel contains 0.864 mol of oxygen gas. how many liters of oxygen gas must be added at constant temper
svet-max [94.6K]

Givens
=====
V = 4.00 L
T = 273oK We're assuming the temperature does not change, just the pressure.
n = 0.864 moles
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Formula
======
PV = n*R*T
P = n*R*T/V
P = 0.864 * 8.314 * 273 / 4
P = 490 kpa


You have to add 1.6 – 0.864 = 0.736 moles of gas.


We have to assume that the temperature and pressure remain the same when we add the 0.736 moles of gas. We are now looking for the volume.


PV = n*R*T

<span> V = 0.736 * 8.314 * 273 / 490</span>

V = 3.41 L Remember this is at about 4 atmospheres so we have to convert to Standard Pressure.

Total Volume = 3.41 + 4.00 = 4.41


V1 * P1 = V2 * P2

P1 = 490 kPa

P2 = 101 kPa

V1 = 7.41 L

V2 = ????


<span> <span> 7.41* 490 = V2 * 101 V2 = 7.41 * 490 / 101 V2 = 35.94 L </span> </span>


<span>You had 4 L now you need 31.94 more.</span> 
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<u>Explanation:</u>

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