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svlad2 [7]
2 years ago
10

An 80,000 kg plane is flying at 900 km/h at a height of 10 kilometers. What is its total mechanical energy? Group of answer choi

ces 478 MJ 250 MJ 10,340 MJ 773 MJ
Physics
1 answer:
Romashka-Z-Leto [24]2 years ago
4 0

The mechanical energy of the given flying object is 10,340 MJ. So the correct choice is 10,340 MJ.

Mechanical energy: The mechanical energy of an object is the sum of its potential energy and kinetic energy.

The formula for the mechanical energy E is:

E=K+U

where K is the kinetic energy and U is the potential energy.

Kinetic energy: The energy possessed by an object due to the motion.

The kinetic energy is given by the formula,

K=(1/2)*(mv^2)

where m is the mass of the object and v is the velocity of the object.

Potential energy: The energy possessed by an object due to its relative position from a given point.

The potential energy is given by the formula,

U=m*g*h

where g is the acceleration due to gravity and h is the height of the object from the ground.

Substitute K=(1/2)*(mv^2) and U=m*g*h in the formula of the mechanical energy to get the following formula,

E=(1/2)*(mv^2)+m*g*h

Given that m=80000 kg, h=10 km, and v=900 km/h, and the value of g is 9.8 m/s^(-2), the value of the total mechanical energy is,

E=(1/2)*(80,000 kg)(900 km/h )^2+(80,000 kg)*(9.8 m/s^(-2))*(10 km)

Note: 1 km= 1000 m and 1 km/h = 5/18 m/s. 1 MJ = 10^(6) J

E=(1/2)*(80,000 kg)*(900*(5/18) m/s )^2+(80000 kg)*(9.8 m/s^(-2))*(10000 m)

E=(1/2)*(80,000 kg)*(250 m/s)^2+7840*10^(6) J

E=2500*10^(6) J+7840*10^(6) J

E=10340*10^(6) J

E=10340 MJ

Learn more about Potential energy here:

brainly.com/question/15647581

#SPJ4

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3 years ago
A 69.5-kg person throws a 0.0475-kg snowball forward with a ground speed of 31.5 m/s. A second person, with a mass of 57.5 kg, c
Leno4ka [110]

Answer:

- After throwing the snow, velocity of the thrower is 2.33 m/s

- the velocity of the receiver is 0.026 m/s

Explanation:

Given the data in the question;

Using conservation of momentum,

Initial thrower has a momentum of mv; m_{totalv

(69.5 kg + 0.0475 kg) × 2.35 m/s = 163.4366 kg.m/s

Now, When he throws it at 31.5 m/s, these constitutes a momentum of;

(0.0475 kg )(31.5 m/s) = 1.49625 kg.m/s

hence his momentum now is: 163.4366 - 1.49625 = 161.94035 kg.m/s

To get his velocity, we say;

161.94035 = mv

{ he lost weight of the snow ball so, m = 69.5 kg )

161.94035 = 69.5 × v

v = 161.94035 / 69.5

v = 2.33 m/s

Therefore, After throwing the snow, velocity of the thrower is 2.33 m/s

Next is the Receiver;

the receiver will gain momentum of 1.49625 kg.m/s

he has no momentum initially and after he catches the snow ball;

1.49625 kg.m/s = mv

1.49625 kg.m/s = ( 57.5 kg +  0.0475 kg ) × v

1.49625 kg.m/s = 57.5475 kg × v

v = ( 1.49625 kg.m/s ) / 57.5475 kg

v = 0.026 m/s

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Answer:

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Explanation:

As we know that flux linked with the coil is given as

\phi = NBA

here we have

A = \pi R_s^2

B = \mu_o N i/L

now we have

\phi = N(\mu_o N i/L)(\pi R_s^2)

now the induced EMF is rate of change in magnetic flux

EMF = \frac{d\phi}{dt} = \mu_o N^2 \pi R_s^2 \frac{di}{dt}/L

now for induced electric field in the coil is linked with the EMF as

\int E. dL = EMF

E(2\pi r_c) = \mu_o N^2 \pi R_s^2 \frac{di}{dt}/L

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E = \frac{(4\pi \times 10^{-7})(6500^2)(0.14^2)(79)}{2(0.20)(3.50)}

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