A uniform, thin, solid door has height 2.20 m, width 0.870 m, and mass 23.0 kg. (a) find its moment of inertia for rotation on i

Question

Doss [256]

3 years ago

13

A uniform, thin, solid door has height 2.20 m, width 0.870 m, and mass 23.0 kg. (a) find its moment of inertia for rotation on i

ts hinges. (b) is any piece of data unnecessary

Physics

1 answer:

vampirchik [111] · Answer 1 · 2022-04-01T11:13:57+03:00

The solution for this problem is:

a. The moment of inertia of the thin door rotating about the hinges axis is given by:

I = 1/3 mw^2 is to solve for the inertia, where: m is the mass and w is the width

= 23.0 x 0.870^2 / 3

= 17.4087 / 3

= 5.8029 kg m^2

b. The height of the door is not required for this calculation.