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Doss [256]
3 years ago
13

A uniform, thin, solid door has height 2.20 m, width 0.870 m, and mass 23.0 kg. (a) find its moment of inertia for rotation on i

ts hinges. (b) is any piece of data unnecessary
Physics
1 answer:
vampirchik [111]3 years ago
8 0
The solution for this problem is:


a. The moment of inertia of the thin door rotating about the hinges axis is given by:

I = 1/3 mw^2 is to solve for the inertia, where: m is the mass and w is the width


= 23.0 x 0.870^2 / 3

= 17.4087 / 3

= 5.8029 kg m^2


b. The height of the door is not required for this calculation.
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It takes 3 half-lives:
1. 1000 -> 500
2. 500 -> 250
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4 years ago
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3 years ago
A wave traveling at 230 m/sec has a wavelength of 2.1 meters. What is the frequency of this wave?
Galina-37 [17]

Answer:

<h2>109.52 Hz</h2>

Explanation:

The frequency of the wave when given it's velocity and wavelength only can be found by using the formula

f =  \frac{c}{ \lambda}  \\

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c is the velocity of the wave in m/s

\lambda is the wavelength in meters

From the question we have

c = 230 m/s

\lambda = 2.1 m

f =  \frac{230}{2.1}  = 109.523809... \\

We have the final answer as

<h3>109.52 Hz</h3>

Hope this helps you

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Answer:

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Explanation:

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