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andrew11 [14]
4 years ago
15

At 517 mm Hg and 24 °C, a sample of gas occuples a volume of 95 ml. The gas is transferred to a 225-ml flask and the temperature

is reduced to -
8.0 °C. What is the pressure of the gas in the flask in mmHg?
Chemistry
2 answers:
vodomira [7]4 years ago
7 0

Answer:

P_2=194.78mmHg

Explanation:

Hello,

In this case, we employ the combined ideal gas law in order to understand the volume-gas-pressure behavior as shown below:

\frac{P_1V_1}{T_1}= \frac{P_2V_2}{T_2}

Hence, solving for the final pressure P2, we obtain (do not forget temperature must be absolute):

P_2=\frac{P_1V_1T_2}{V_2T_1}=\frac{517mmHg*95mL*(-8.0+273.15)K}{(24+273.15)K*225mL}\\ \\P_2=194.78mmHg

Best regards.

kifflom [539]4 years ago
3 0

Answer:

195mmHg is the pressure of the flask

Explanation:

Combined gas law defines the relationship of pressure, absolute temperature and volume of a gas under different conditions. The formula is:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

In the problem, initial conditions of the gas are:

517mmHg = P₁

24°C + 273.15 = 297.15K = T₁

95mL = V₁

And final conditions are:

225mL = V₂

8.0°C + 273.15 = 265.15K = T₂

Replacing:

\frac{517mmHg*95mL}{297.15K} =\frac{P_2*225mL}{265.15K}

P₂ = <em>195mmHg is the pressure of the flask</em>

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A certain gas is present in a 12.0 L cylinder at 4.0 atm pressure. If the pressure is increased to 8.0 atm the volume of the gas
diamong [38]
There are 3 parts in this question:
1) To find the initial Boyle's constant k_{i}
2) To find the final Boyle's constant k_{f}
3) To verify whether gas is obeying Boyle's law or not

Given data:
The initial volume of the cylinder(in litres) = V_{i} = 12.0 L
The initial pressure(in atmospheric pressure) = P_{i} = 4.0 atm

The final pressure(in atmospheric pressure) = P_{f} = 8.0 atm
The final volume of the cylinder(in litres) = V_{f} = 6.0 L

First you need to know what Boyle's law is:
<span>Boyle's law states that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature.
</span>
The Mathematical form of Boyle's law is:
P =  \frac{k}{V}

Where,
P = Pressure
V = Volume of the gas
k = Boyle's constant

Now let's solve aforementioned parts one by one:
1. 
The initial volume of the cylinder(in litres) = V_{i} = 12.0 L
The initial pressure(in atmospheric pressure) = P_{i} = 4.0 atm
The Boyle's constant = k_{i} = ?

According to the Boyle's law,

P_{i} = \frac{k_{i}}{V_{i}}

=> k_{i} =  P_{i}V_{i}
Plug-in the values in the above equation, you would get:
k_{i} = 4.0 * 12.0 = 48

Ans-1) k_{i} = 48

2.
The final pressure(in atmospheric pressure) = P_{f} = 8.0 atm
The final volume of the cylinder(in litres) = V_{f} = 6.0 L
The Boyle's constant = k_{f} = ?

According to the Boyle's law,

P_{f} = \frac{k_{f}}{V_{f}}

=> k_{f} =  P_{f}V_{f}
Plug-in the values in the above equation, you would get:
k_{f} = 8.0 * 6.0 = 48

Ans-2) k_{f} = 48

3.
In order to verify Boyle's law, the initial Boyle's constant should be EQUAL to the final Boyle's constant, meaning:

k_{i} = k_{f}

Since,
k_{i} = 48
k_{f} = 48

Therefore,
48=48.

Ans-3) Hence proved: The gas IS obeying the Boyle's law.

-i

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