The attraction will decrease. Hope I helped :)
Answer:
According to Newton's third law of motion, for every action, there is an equal and opposite reaction. When the man jumps from a boat, he applies force on the boat due to which boat moves backward. An equal force is exerted by the boat on the man which helps the man to jump out of the boat.
Answer:
μ = 0.66, therefore if it compiesy with the regulations
Explanation:
Let's solve this exercise in part, let's start by finding with kinematics the acceleration of man
y = v₀ t + ½ a t²
as it starts from rest the initial velocity is zero
y = ½ a t²
a =
a =\frac{2 \ 4.38}{1.21^2}
a = 6.46 m / s²
Now let's use Newton's second law,
Axis y
N- W = 0
N = W
N = m g
X axis
on this axis the man exerts a backward force and by the law of action and reaction the floor exerts a forward force of the same magnitude, this forward force is the friction force.
fr = m a
the friction force has an expression
fr = my N
let's substitute
μ mg = m a
μ = a / g
let's calculate
μ = 6.46 / 9.8
μ = 0.66
therefore if you comply with the regulations
What it means to write something in standard form would mean just to have a simple humber. For example the standard form for 500+60+1 would be 561.
Options:
a) 10 m/s²
b) 8 m/s²
c) 4.4 m/s²
d) More information is needed
Answer:
d) More information is needed
Explanation:
The acceleration due to gravity at an altitude h above the surface of a planet is given by the equation:
.................(1)
where the altitude above the surface of the planet X, h = 3000 km
Acceleration due to gravity at the surface of the planet, g₀ = 10 m/s²
To be able to get the acceleration due to gravity, g, at an altitude h above the surface of the planet, all parameters must be substituted into equation (1).
Unfortunately, the radius, R, of the planet, X, is not given. This means that there are no sufficient parameters(information) to find the acceleration due to gravity at an altitude h above the surface of the planet.