Answer:
![30 N \cdot m](https://tex.z-dn.net/?f=30%20N%20%5Ccdot%20m)
Explanation:
The torque applied by a force can be calculated as
![\tau = F d sin \theta](https://tex.z-dn.net/?f=%5Ctau%20%3D%20F%20d%20sin%20%5Ctheta)
where
F is the magnitude of the force
d is the length of the arm
is the angle between the direction of the force and the arm
In this problem, we have
F = 15 N
d = 2.0 m
![\theta=90^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D90%5E%7B%5Ccirc%7D)
Substituting into the equation, we find
![\tau = (15)(2.0) sin 90^{\circ}=30 N \cdot m](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%2815%29%282.0%29%20sin%2090%5E%7B%5Ccirc%7D%3D30%20N%20%5Ccdot%20m)
Vo= 331+0.6T
360=331+0.6T
360-331=0.6T
29=0.6T
0.6T/29
T=6/290 so change it to simplest form and us formulas good luck