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S_A_V [24]
3 years ago
12

A mining company plans to improve the infrastructure in a location to start mining activities. The company calculated the costs

and earnings listed below to find out if mining would be economically feasible in the location.
A: Cost of land for mining
B: Cost of equipment
C: Cost of labor
D: Miscellaneous costs related to mining
E: Cost of reclamation
F: Earnings from selling the resulting mineral

How can the mining company best decide whether mining activities in the location would be economically feasible?

Select one:
a. by confirming that F is greater than A + B + C + D + E
b. by confirming that D is greater than A + B + C + E + F
c. by confirming that B is lesser than A + C + D + E + F
d. by confirming that C is lesser than A + B + D + E + F
Physics
1 answer:
vfiekz [6]3 years ago
5 0
To decide whether any project is economically feasible or not, the profit from selling the product needs to be greater than the cost of actually producing or making the product.

In the given question, our project is mining. 
The total costs for the project = A + B + C + D + E
The total profit for the project = F

Therefore, to verify that the project is economically feasible, the profit (F) needs to be greater that the cost (A + B + C + D + E)

Based on the above, the best choice would be:
<span>a. by confirming that F is greater than A + B + C + D + E</span>
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A cheetah bites into its prey. One tooth exerts a force of 320 N. The area of the point of the tooth is 0.5 cm². The pressure of
mote1985 [20]

Answer:

<h2>640N/cm^2</h2>

Answer D is correct

Explanation:

pressure =  \frac{force}{area}  \\  =  \frac{320}{0.5}  \\  = 640

hope this helps

brainliest appreciated

good luck! have a nice day!

6 0
3 years ago
An automobile traveling along a straight road increases its speed from 72 ft/s to 84 ft/s in 180 ft. if the acceleration is cons
Nikolay [14]
The equation that would allow us to calculate for the acceleration given the distance is written below,

      a = (Vf² - Vo²) / 2d

where a is the acceleration, Vf is the final velocity, Vo is the initial velocity, and d is distance. 

Substituting the known values,
    a = ((84 ft/s)² - (72 ft/s)²) / 2(180 ft) = 5.2 ft/s²

Then, the equation that would relate the initial velocity, distance, acceleration and time is calculated through the equation,
      
     d = Vot + 0.5at²

Substituting the known values,
    180 = 72(t) + 0.5(5.2)(t²)

The value of t from the equation is 2.3 s

<em>ANSWER: 2.3 s</em>
5 0
4 years ago
A body of mass 40kg is accelerating at a
jok3333 [9.3K]
Momentum = (mass) x (speed)

Mass is constant, so the rate of change of momentum is
                        (mass) x (rate of change of speed) .

But (rate of change of speed ) is just acceleration.

So the rate of change of momentum is (mass) x (acceleration).

But (mass) x (acceleration) is Force.

So Force is the rate of change of momentum.    Verrrrrrrry interesting !

In this problem, Force = (40 kg) x (9 m/s²) = 360 newtons.

One 'Newton' is one kilogram-meter per second² .
Unit of momentum is (kilogram)-(meter per second), so 'newton'
is also a unit of time rate of change of momentum.

Rate of change of momentum is 360 momentum units per second.
8 0
4 years ago
Read 2 more answers
A spring has a force constant k, and an object of mass m is suspended from it. The spring is cut in half and the same object is
kenny6666 [7]

Answer:

f2/f1 = \sqrt{2}

Explanation:

From frequency of oscillation

f = 1/2pi *\sqrt{k/m}

Initially with the suspended string, the above equation is correct for the relation, hence

f1 = 1/2pi *\sqrt{k/m}

where k is force constant and m is the mass

When the spring is cut into half, by physics, the force constant will be doubled as they are inversely proportional

f2 = 1/2pi *\sqrt{2k/m}

Employing f2/ f1, we have

f2/f1 = \sqrt{2}

3 0
3 years ago
How much work is needed to move an object from one position to another when both positions are located the same distance from th
Vladimir79 [104]

Answer:

<em>The product of the object's weight and the horizontal distance between the two positions.</em>

<em></em>

Explanation:

Work is the product of force and the distance through which this force is moved. The distance moved can be vertical, or horizontal. For two bodies located the same distance from the center of the earth, the work done will be the product of the weight of the product and the horizontal distance between the two positions. <em>If the vertical work is needed, then the work is zero, since there is no height gradient between them</em>.

8 0
4 years ago
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