Question

Determine the molar mass of a 0.314-gram sample of gas having a volume of 1.6 l at 287 k and 0.92 atm. show your work.

Answer 1

As per Ideal gas equation, molar mass of the gas is 5.032 g/mo

We’ll begin by calculating the number of mole of the gas. This can be obtained as follow:

Volume (V) = 1.6 L

Temperature (T) = 287 K

Pressure (P) = 0.92 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =?

According to Ideal gas equation , PV = nRT

0.92 × 1.6 = n × 0.0821 × 287

1.472 = n × 23.5627

Divide by 23.5627

n = 1.176 / 23.5627

n = 0.0624 mole

Finally, we shall determine the molar mass of the gas. This can be obtained as follow:

Mass of gas = 0.314 g

Number of mole = 0.0624 mole

Mole = $\frac{mass}{molar mass}$

0.0624 = $\frac{0.314}{molar mass}$

Cross multiply

0.0624 × molar mass of gas = 0.314

Divide by 0.0624

Molar mass of gas =  $\frac{0.314}{0.0624}$

Molar mass of gas = 5.032 g/mo

Therefore the Molar mass of gas is 5.032 g/mo

Learn more about  Ideal gas equation here:

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