Determine the molar mass of a 0.314-gram sample of gas having a volume of 1.6 l at 287 k and 0.92 atm. show your work.
1 answer:
As per Ideal gas equation, molar mass of the gas is 5.032 g/mo
We’ll begin by calculating the number of mole of the gas. This can be obtained as follow:
Volume (V) = 1.6 L
Temperature (T) = 287 K
Pressure (P) = 0.92 atm
Gas constant (R) = 0.0821 atm.L/Kmol
Number of mole (n) =?
According to Ideal gas equation , PV = nRT
0.92 × 1.6 = n × 0.0821 × 287
1.472 = n × 23.5627
Divide by 23.5627
n = 1.176 / 23.5627
n = 0.0624 mole
Finally, we shall determine the molar mass of the gas. This can be obtained as follow:
Mass of gas = 0.314 g
Number of mole = 0.0624 mole
Mole =
0.0624 =
Cross multiply
0.0624 × molar mass of gas = 0.314
Divide by 0.0624
Molar mass of gas =
Molar mass of gas = 5.032 g/mo
Therefore the Molar mass of gas is 5.032 g/mo
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The Molarity of the HCl Solution requires the addition of 24.6 mL of titrant is 0.0836 M (to 3 significant figures)
<h3>What is Titrant?</h3>A reagent solution of precisely known concentration that is added in titration
Given reaction HCl + NaOH ===> NaCl + neutralization reaction
Note that the mole ratio is 1:1 meaning that 1 mole HCl reacts with 1 mole NaOH to produce 1 mole NaCl and 1 mole
Find moles of NaOH used:
18.45 ml x 1 L/1000 ml x 0.085 mol/L = 0.002091 moles NaOH used
This meant that there must be 0.002091 moles of HCl present in the 25.0 mls.
We want to find the molarity (M) which is moles HCl/liter of solution. We know the moles, and we also know the liters of solution (25.0 mls x 1 L / 1000 mls = 0.025 liters)
M = 0.002091 moles HCl / 0.025 liters = 0.08364 M = 0.0836 M (to 3 significant figures)
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Answer:
hydrogen=161mmHg
Explanation:
