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Tom [10]
3 years ago
9

Which element experiences greater London dispersion forces?

Chemistry
2 answers:
Pani-rosa [81]3 years ago
8 0
The answer is D: Iodine.
Xelga [282]3 years ago
4 0

The correct answer is

Iodine

:)

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FeSO4(aq) + K3PO4 (aq) —>
ch4aika [34]

An ionic equation is a chemical equation in which the electrolytes in aqueous solution are described as dissociated ions.

<h3>What is the difference between ionic equation and net ionic equation?</h3>
  • A complete ionic equation also contains the spectator ions, whereas a net ionic equation just displays the chemical species that are involved in a reaction.
  • A molecular formula has two or more atoms bonded together, whereas a chemical formula can only refer to one atom. They are both elements, and their chemical symbols are unchanged.
  • An ionic equation is a chemical equation in which the electrolytes in aqueous solution are described as dissociated ions. It is similar to a molecular equation in that it expresses compounds as molecules.

3FeSO4(aq) + 2K3PO4(aq) = Fe3(PO4)2(s) + 3K2SO4(aq)

ionic equation : 3Fe(2+)(aq) + 3SO4(2-)(aq)+ 6Na(+)(aq) + 2PO4 (3-) (aq) → Fe3(PO4)2(s)+ 6Na(+) + 3SO4(2-)(aq)

net ionic equation: 3Fe(2+)(aq)  + 2PO4 (3-)(aq) → Fe3(PO4)2(s)  

K2CO3(aq) + CdI2(aq) = 2KI(aq) + CdCO3(s)

net ionic equation for K2CO3(aq) + CdI2(aq) = 2KI(aq) + CdCO3(s).

2HNO3 + CaCO3 = Ca(NO3)2 + H2O + CO2

ionic equation :  CaCO3(s) + 2H+(aq) → Ca2+(aq) + CO2(g) + H2O()

To learn more about :   Ionic equation

Ref :  brainly.com/question/19705645

#SPJ13

5 0
1 year ago
How many grams of copper would have the same number of atoms as 139.82 grams of argon
lianna [129]

Answer:

Lesson 3 Quiz ReturntoAssessmentList Part 1 of 4 - 4.0/ 8.0 Points Question 1 of ... in the balloon containing regular air D.Each balloon has an equal number of atoms. ... The purity of those pre-1982 pennies are really about 95% copper (5% zinc ... that had a mass of 3.11 grams, how many atoms of copper would you have?

Explanation:

7 0
3 years ago
I NEED HELP PLEASE! (Made it worth A LOT of points!!!)
Scilla [17]

Answer:

the third one.

Explanation:

4 0
3 years ago
In 1808, John Dalton proposed a series of statements regarding the atom that became known as Dalton's postulates or Dalton's ato
Oduvanchick [21]

Answer:

The all 4 the given statements are part of Dalton's atomic theory.

Explanation:

Dalton's postulates or Dalton's atomic theory:

  • Matter is made up of small particles termed as atom.
  • Atoms are indivisible particle.
  • Atoms of different element have different masses and properties.
  • Atoms of the same element have the identical size, mass, and structure.
  • During chemical reaction, rearrangement of atoms takes place.
  • Atoms of different different combines together to form new compounds in simple whole number ratio.
6 0
3 years ago
10. (a) Describe how the structure of an alloy is different to a pure metal
Oxana [17]
1.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element that reacts with water to produce a lilac flame

2.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element used as an inert atmosphere

3.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element that has a valency of 3

4.Write a balanced chemical equation for the reaction between potassium and water. (Non-anonymous question). .
(1 Point)

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5.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element with a fixed valency of 2 that not is not in group 2

Help
4 0
3 years ago
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