Plasma Membrane, nucleus, and cytoplasm
<u>Given:</u>
Surface area at the narrow end, A1 = 5.00 cm2
Force applied at the narrow end, F1 = 81.0 N
Surface area at the wide end, A2 = 725 cm2
<u>To determine:</u>
Force F2 applied at the wide end
<u>Explanation:</u>
Use the relation
F1/A1 = F2/A2
F2 = F1*A2/A1 = 81.0 N * 725 cm2/5.00 cm2 = 11,745 N
Ans: (b)
The force applied at the wide end = 11,745 N
Answer:
Carbon - 14
Oxygen - 16
Nitrogen - 15
Sulphur - 16
Explanation:
The question above is related to the "Periodic Table of Elements" which shows the proper arrangement of elements in a table. Every element falls on a<em> group/family</em> within the table. Each group has its own number, and the table has a total of<u> 18 groups</u><em> (from left to right). </em>They are classified according to <em>similarities in their characteristics</em>. For example, group 1 is composed of <em>alkali metals</em> while group 2 is composed of<em> alkali earth metals</em>.
Answer:19. He says that he’s been really tired since several weeks ago. 20. A friend of us is going to pick us up at the airport. 21. I’ve worked like a waiter in the past, but I wouldn’t want to do it again. 22
Explanation:
5.241 in scientific notation
5.241 × 10^0
