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Keith_Richards [23]
3 years ago
12

Substitution method of y=x+5 and 5x+y=3

Mathematics
2 answers:
Levart [38]3 years ago
7 0
To solve by substitution, you need to fill in the value for either x or y. Since y = x + 5, you already have the y value. It's x + 5. Now you need to find x before you can go any further. So let's take 5x + y = 3 and fill x + 5 in for y. 5x + y = 5 5x + x + 5 = 3 Now solve for x. 5x + x + 5 = 3 6x + 5 = 3 6x = 3 - 5 6x = -2 x = -2/6 or -0.33 Now solve x + 5 for y. y = x + 5 y = -0.33 + 5 y = 4.67 So x = -0.33 and y = 4.67
vaieri [72.5K]3 years ago
3 0
Solve for the first variable in one of the equations,then substitute the result into the other equation.
(-1/3,14/3) 

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Write the product as a sum: 14cos(39x)sin(19x)
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Recall that

sin(<em>a</em> + <em>b</em>) = sin(<em>a</em>) cos(<em>b</em>) + cos(<em>a</em>) sin(<em>b</em>)

sin(<em>a</em> - <em>b</em>) = sin(<em>a</em>) cos(<em>b</em>) - cos(<em>a</em>) sin(<em>b</em>)

Adding these together gives

sin(<em>a</em> + <em>b</em>) + sin(<em>a</em> - <em>b</em>) = 2 sin(<em>a</em>) cos(<em>b</em>)

To get 14 cos(39<em>x</em>) sin(19<em>x</em>) on the right side, multiply both sides by 7 and replace <em>a</em> = 19<em>x</em> and <em>b</em> = 39<em>x</em> :

7 (sin(19<em>x</em> + 39<em>x</em>) + sin(19<em>x</em> - 39<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

7 (sin(58<em>x</em>) + sin(-20<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

7 (sin(58<em>x</em>) - sin(20<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

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3 years ago
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Answer:

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The cosine of 45° is the x-coordinate of the point on the unit circle where the line y=x intersects it. That is, it is the positive solution to the equation ...

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lina2011 [118]

Answer:

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Step-by-step explanation:

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If log, 7 -3 what is the value of x?<br> A. 21<br> B. 3V7<br> C. 37<br> D. 343
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