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vfiekz [6]
2 years ago
7

If it costs $1.40 per square foot to install the garden, what is the cost for plan A?

Mathematics
1 answer:
Mila [183]2 years ago
6 0

Answer:

$9.80 bro for plan A i hope i help you

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Good Treads and Speed Tracks manufacture tires. Good Treads claims that their tires last longer than Speed Tracks tires. A car c
Crazy boy [7]
The answer is B... good treads claim is false therefore it can be concluded that speed tracks tires last longer than good treads tires 

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3 years ago
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A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int
Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}

By expanding the previous equation:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0

Since there is no accumulation within the tank, expression is simplified to this:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}, where c(0) = 0 \frac{pounds}{gallon}.

\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}

The solution of this equation is:

c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})

The salt concentration after 8 minutes is:

c(8) = 0.166 \frac{pounds}{gallon}

The instantaneous amount of salt in the tank is:

m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds

3 0
3 years ago
Anwser true or false
m_a_m_a [10]
False because doing the math doesn’t match
6 0
2 years ago
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3y-x=3 and x is four times the value of y what is the value of x-y?
Aleonysh [2.5K]

Answer:

x - y = -9

Step-by-step explanation:

from the equation

3y - x = 3

and x is four times the value of y

i.e  x = 4y

put x  = 4y into the first equation

we have;

3y  - 4Y = 3

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Divide both sides by -1

we have

y = -3

so put y = -3 in the 2nd equation

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x = 4 × -3

x = -12

therefore x = -12 and y = -3

so tho find x - y

we have

-12 - (-3)

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therefore x - y = -9

7 0
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elena-14-01-66 [18.8K]

Answer:

`18. x=9

19. x=4

20. x=25,5

21. x=3

22. x=3,5

23. x=10

Step-by-step explanation:

5 0
2 years ago
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