Let m=n-4
n - 4 + 5n = 20
6n = 24
> n = 4
m = 4 - 4
> m = 0
(0,4)
105 different outfits can wear on an individual day
<em><u>Solution:</u></em>
I have 7 button down shirts, 5 pairs of pants and 3 pairs of shoes that I can wear to work
To find: Number of different outfits can I wear on an individual day
First he has to decide on a pair of pants and he has 5 different choices
For each of those choices he has a choice of 7 different button down shirts, so that gives him 5 x 7 = 35 different pant/shirt combinations
For each of those 35 different pant/shirt combinations, he has 3 pairs of shoes he could select, so altogether he has 35 x 3 = 105 different outfits
In short we can say,
different outfits = 7 x 5 x 3 = 105
So there 105 different outfits can wear on an individual day
A + (-5) = -12
First isolate your variable so move the -5 over (by adding 5 to both sides)
Then you will have a = -12+5
Simplify and you get A= -7
Answer:
thats not a qustion im sorry i cannot answer it
Step-by-step explanation:
It would be 12 because 25*4= 1 hour wvery 4 days she reads a hour
