The volume that sticks out of the water is 83 m³.
To find the answer, we need to know about the archimedes principle.
<h3>What's archimedes principle?</h3>
- It says that when an object is on a water surface, the amount of force on the object is equal to the weight of water displaced by it.
- Mathematically, weight of the object= weight of water displaced
<h3>What's the volume of an object remain on the water surface, if the density and mass of the object are 941.0 kg/m³, 1039.0 kg respectively?</h3>
- Let V = volume of the object,
- v= volume of water displaced
- V-v = volume that sticks out of the water
- Weight of the object = V× density of object × g
- Weight of water displaced= v× density of water × g
- As per archimedes principle, V× density of object × g=v× density of water × g
- V-v = density of water - density of object
= 1024 - 941 = 83 m³
Thus, we can conclude that the volume that sticks out of the water is 83 m³.
Learn more about the archimedes principle here:
brainly.com/question/775316
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