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3 years ago

14

If R1 is 2 ohms and R2 is 3 ohms and R3 is 5 ohms...what is total resistance?

1 answer:

OLEGan [10]3 years ago

5 0

Answer:

10 ohm

Explanation:

Since the resistors are arranged in series, their total resistance is their sum.

Hence, Total R = 2+3+5 = <u>10 ohm</u>

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Explain the role of energy in changes <br> of state.

slava [35]

A liquid requires enthalpy of vaporization to transform into vapor or gas at its boiling point. Here the element absorbs heat from surroundings or heat source.

This energy is used in breaking the forces of attraction among the atoms and molecules of the element. The molecules get separated to higher distances. The energy is converted in to the kinetic energy of the molecules in gaseous form and into the internal energy in terms of the temperature of the gas.

3 0

3 years ago

____ is a pesticide that influenced society by increasing crop yield, but it also caused human and animal sickness.

Ilya [14]

I think your answer would be DDT, but don't hold me to it

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3 years ago

What is the weight of an object if the mass is 78 and the gravity is 9.5

zmey [24]

The answer should be 741 N.

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9.5*78 is 741

8 0

2 years ago

What is the kinetic energy of a 1.00g hailstone falling at 8.50m/s

bearhunter [10]

Answer:

36.125 J

Explanation:

The formula for kinetic energy is KE = .5(m)(v²).

Using the given information, mass = 1 g and v = 8.50. Plug that information into the equation. KE = .5(1)(8.50²) = 36.125 J.

4 0

3 years ago

A 12.5843-gram sample of metal bromide, MBr4, was dissolved and, after reaction with silver nitrate, AgNO3, all of the bromide w

barxatty [35]

Answer:

zirconium

Explanation:

Given, Mass of AgBr(s) = 23.0052 g

Molar mass of AgBr(s) = 187.77 g/mol

The formula for the calculation of moles is shown below:

$Moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles\ of\ AgBr= \frac{23.0052\ g}{187.77\ g/mol}$

$Moles\ of\ AgBr= 0.1225\ mol$

The reaction taking place is:

$MBr_4+4AgNO_3\rightarrow 4AgBr+M(NO_3)__4$

From the reaction,

4 moles of AgBr is produced when 1 mole of $MBr_4$ undergoes reaction

1 mole of AgBr is produced when 1 / 4 mole of $MBr_4$ undergoes reaction

0.1225 mole of AgBr is produced when $\frac {1}{4}\times 0.1225$ mole of $MBr_4$ undergoes reaction

Moles of $MBr_4$ got reacted = 0.030625 moles

Mass of the sample taken = 12.5843 g

Let the molar mass of the metal = x g/mol

So, Molar mass of $MBr_4$ = x + 4 × 79.904 g/mol = 319.616 + x g/mol

Thus,

$0.030625 = \frac{12.5843}{319.616 + x}$

Solve for x,

we get, x = 91.2999 g/mol

<u>The metal shows +4 oxidation state and has mass of 91.2999 g/mol . The metals is zirconium.</u>

8 0

3 years ago