The x-intercept is the value of x when y is equal is zero. It is the point in the x-axis intersected by the line. The y-intercept is the value of y when x is zero. It is where the line intersects in the axis. Therefore, for the given equation:
<span>y=−12x+4
</span><span>y=−12(0)+4 = 4<--------y-intercept
</span><span>0=−12x+4
x = 1/3 <--------x-intercept</span>
Answer:
The distribution of multiple groups can be compared by analyzing the histogram of two data. The histogram analysis of multiple groups can be compared and analyzed by observing the following features of histograms. Shape: whether the shapes of distribution are alike or different from each other.
Step-by-step explanation:
Answer:
The correct answer is A..
Step-by-step explanation:
From the Invertible Matrix Theorem (IMT) we have a set of equivalent conditions to determine if a square matrix is invertible or not. In particular, it says that a square matrix of dimension tex]n\times n[/tex] is invertible if and only if, its columns span the vector space tex]R^n[/tex].
In the particular case of this exercise we have a matrix of dimension tex]5\times 5[/tex]. So, by the Invertible Matrix Theorem its columns must span the vector space tex]R^5[/tex]. Now, according to the statement of the exercise this condition does not hold. Hence, the given matrix cannot be invertible.
Answer: shade too the left
Step-by-step explanation: i don't know what closed point is but if you use something called desmos then press start graphing and put in that equation it will give you the graph you need
the standard form of a quadratic formula is
y = ax^2 + bx + c
in this case you will solve using foil method
(× - 4)(x + 3)
<em>(</em><em>x</em><em> </em><em>×</em><em> </em><em>x</em><em>)</em><em> </em><em>+</em><em>(</em><em> </em><em>x</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>)</em><em>(</em><em>-</em><em> </em><em>4</em><em> </em><em>×</em><em> </em><em>x</em><em>)</em><em> </em><em>(</em><em> </em><em>-4</em><em>)</em><em>×</em><em> </em><em>3</em><em>)</em><em>)</em>
<em>x</em><em>^</em><em>2</em><em> </em><em>+</em><em> </em><em>3x</em><em> </em><em>-</em><em> </em><em>4x</em><em> </em><em>-12</em>
<em>x</em><em>^</em><em>2</em><em> </em><em>-</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>1</em><em>2</em>
<em>therefore</em><em> </em>
<em>y</em><em> </em><em>=</em><em> </em><em>x^</em><em>2-</em><em> </em><em>x</em><em> </em><em><u>-</u></em><em><u> </u></em><em><u>1</u></em><em><u>2</u></em><em><u> </u></em>