Answer:
(a) B' U U = { f,g,h,p,q,r}
(b) B ∩ U = {g,q,r}
Step-by-step explanation:
Greetings !
(a) B/c B'= {X: X∈U and X∉B}
thus,B'= {f,h,p}
B' U U= {f,h,p} U {f,g,h,p,q,r}
= {f,g,h,p,q,r}
(b) B ∩ U= {g,q,r}
<em>13.1</em>
A = bh
~~~~~~~
= 16 , = 9
A = 16 × 9 = 144
From another side area of parallelogram with hight "h" base "b"
11h = 144
<em>h</em> = 144 ÷ 11 ≈ <em>13.1</em>
f(0)=2
f(x)=-3x +2
f(0)=-3(0) +2
f(0)= 0 +2