Question

A boat moves through the water with two forces acting on it. One is a 1,575-N forward push by the water on the propeller, and the other is a 1,200-N resistive force due to the water around the bow. (Review attachment)
(a) What is the acceleration of the 1,100-kg boat?

______ m/s2

(b) If it starts from rest, how far will the boat move in 20.0 s?

______ m


(c) If it starts from rest, how far will the boat move in 20.0 s?

______ m/s

Answer 1

(a) The acceleration of the 1,100-kg boat is 0.341 m/s².

(b) The distance covered by the boat is 68.2 m.

(c) The speed of the boat is 6.82 m/s.

Acceleration of the boat

Net force on the boat = 1,575 N - 1,200 N = 375 N

F(net) = ma

a = F(net)/m

a = 375/1100

a = 0.341 m/s²

Distance moved in 20 s

s = ut + ¹/₂at²

s = 0 + ¹/₂(0.341)(20)²

s = 68.2 m

Speed of the boat in 20 s

v = u + at

v = 0 + 0.341(20)

v = 6.82 m/s

Thus, the acceleration of the 1,100-kg boat is 0.341 m/s², the distance covered by the boat is 68.2 m and the speed of the boat is 6.82 m/s.

Learn more about acceleration here: brainly.com/question/14344386

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