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nataly862011 [7]
3 years ago
13

Are the two atoms shown below in the image from the same element?

Physics
1 answer:
kvasek [131]3 years ago
7 0

The answer is yes

They are isotopes.

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(Cr(NH3).](Co(CN)6) is a coordination complex
never [62]

Answer:19.51%

Explanation:

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3 years ago
How do asteroids and comets differ?
aalyn [17]

Answer:

Explained

Explanation:

Asteroids: Asteroids are generally made up of rocky material, metals and their size are large in  comparison to comets. Asteroid belt is found between Jupiter and Mars.

Comets: Comets are made up of ice, dust and rocky material. Generally smaller in size and are far from the Sun. With each orbit nearing the sun ice of the comet vaporize in form of blazing tail.

4 0
3 years ago
The Cajun Cliffhanger at Great AMerica is a ride in which occupants line the perimeter of a cylinder and spin in a circle at a h
12345 [234]

Explanation:

Centripetal Force is the force that keeps the object's rotation in a circular path and it's always directed towards the center of rotation. Mathematically, it is given as,

F_{c} = \frac{mv^{2} }{r}

From this equation it can be concluded that the centripetal force is proportional to the product of mass and the square of velocity. It is inversely proportional to the object's distance from the center.

Now in the above mentioned case, when the cylinder begins spinning very rapidly and it's speed becomes double. Then by applying the above equation we conclude that " the force will be increased four times if the speed is doubled as it is proportional to square of speed."

5 0
3 years ago
determine the greates possile acceleration of the 975 kg race car so that its front wheels do not leace the gorund
wolverine [178]

<u>Answer</u>:

The greatest possible acceleration of the car is a_G= 6.78 m/s^2

<u>Explanation</u>:

N_A+N_B-Mg = 0

-N_Aa +N_B(b-a)- \mu_s N_Bh - \mu_s N_Ah = 0

0.8N_B +0.8N_A = 975a_G

N_A+N_B = 9564.75 -------------(1)

-N_A(1.82) + N_B(2.20 -1.82) -0.9N_B(0.55)-0.8N_A(0.55)=0

-N_A(1.82) +0.38 N_B -0.44N_B -0.44N_A=0

-2.26N_A -0.06N_B= 0 ----------------(2)

Solving the equation (1) and(2)

N_A + N_B = 9564.75

-2.26N_A-0.06N_B=0

N_A = -260.85N

N_B = 9825.60N

\mu_s N_B + \mu_s N_A = 975a_G

0.8(9825.60)+0.8(-260.85) = 975a_Ga_G=\frac{7651.8}{975}a_G_1=7.4848m/s^2

Next lets assume that the front wheels contact with the ground N_A = 0

F_B = Ma_G

N_B = M_g

N_B - M_g = 0

N_B(b-a) –F_Bh = 0

F_B = 975a_G

N_B-975(9.8) = 0

N_B=9564.75N

9564.75(2.20 -1.82) -F_B(0.55)=0

\frac{3634.605}{0.55}=F_B

F_B = 6608.3

F_B = Ma_G

6608.3 = 975a_G

a_G = 6.7778 m/s^2

a_G_2 = 6.78m/s^2

Choosing the critical case

a_G = min(a_G_1 ,a_G_2)

a_G = min(7.848, 6.78)

a_G= 6.78 m/s^2

3 0
4 years ago
Electromagnets project student guide <br>y’all i need helppppo
Masja [62]

Answer:

I don't know

Explanation:

you need then search here

7 0
2 years ago
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