Answer:
The sample rate determines the maximum receive bandwidth of a direct digital conversion SDR. An analog signal must be sampled at twice the rate of the highest frequency component of the signal by an analog-to-digital converter so that the signal can be accurately reproduced.
Explanation:
Answer:
Calcium
hope this helped mah dude :>
Answer:
The final velocity of cart 1 is 3m/s
Explanation:
From principle of conservation of linear momentum, which states that sum of the momentum before collision is equal to the sum of the momentum after collision.
Momentum, P is given as mass x velocity.
ΔP = Δmv = m₁u₁ +m₂u₂ = m₁v₁ + m₂v₂
Assumptions:
- If the two carts are moving on frictionless track, then limiting frictional forces due to their weights are negligible.
- After the elastic collision, the two carts will move separately with different velocity
u₁ + u₂ = v₁ + v₂;
where;
u₁ and u₂ are the initial velocity for cart 1 and cart 2 respectively
v₁ and v₂ are the final velocity for cart 1 and cart 2 respectively
1 m/s + 5 m/s = v₁ + 3m/s
6 m/s = v₁ + 3m/s
v₁ = 6 m/s - 3m/s = 3m/s
Therefore, the final velocity of cart 1 is 3m/s
Here, F = m * a
F = m * v/t
Here, m = 81 Kg
v = 22 m/s
t = 1,4 s
Substitute their values,
F = 81 * 22/1.4
F = 81 * 15.71
F = 1273 N
So, Closest value from your options is 1300 N
In short, Your Answer would be Option B
Hope this helps!
Answer:
The K.E is maximum when the child is at the vertical position and the P.E is maximum at the extreme deviated position from the vertical.
Explanation:
- A child is swinging on swing up and down has both kinetic and potential energy.
- The total mechanical energy of the system is conserved throughout the system. At any instant the total mechanical energy is given by,
E = K.E + P.E
- The K.E is maximum when the child is at the vertical position.
- The P.E is maximum at the extreme deviated position from the vertical.
- And when K.E is maximum P.E becomes minimum and vice versa as per the law of conservation of energy.
