Generally, the internal resistance of the new battery is small, about 0.2 euros, while the old battery is large, close to 1 euro ，
Search Results<span>Use BFS to determine the length of the shortest v-w-path. Then use DFS to find thenumber of the v-w-shortest paths such that two nodes are connected and the length of path equals to the output of BFS. But the running time of this plan is O(m+n)+O(m+n). Also I've tried to modify the Dijkstra algorithm.</span>
<span>I found out F2 and its correct just need help in solving the other parts </span>
<span>F2 = 4.5 N </span>
(a) The maximum potential difference across the resistor is 339.41 V.
(b) The maximum current through the resistor is 0.23 A.
(c) The rms current through the resistor is 0.16 A.
(d) The average power dissipated by the resistor is 38.4 W.
<h3>Maximum potential difference</h3>
Vrms = 0.7071V₀
where;
V₀ = Vrms/0.7071
V₀ = 240/0.7071
V₀ = 339.41 V
<h3> rms current through the resistor </h3>
I(rms) = V(rms)/R
I(rms) = (240)/(1,540)
I(rms) = 0.16 A
<h3>maximum current through the resistor </h3>
I₀ = I(rms)/0.7071
I₀ = (0.16)/0.7071
I₀ = 0.23 A
<h3> Average power dissipated by the resistor</h3>
P = I(rms) x V(rms)
P = 0.16 x 240
P = 38.4 W
Learn more about maximum current here: brainly.com/question/14562756
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Answer: 24.7 degrees Max
Explanation:
m*g = 3 * 9.8 = 29.4 N. = Wt. of book.
Fp = 29.4*sin A = Force parallel to the
plank.
Fn = 29.4*Cos A = Force perpendicular to
the plank.
Fs = u*Fn = 0.46*29.4*Cos A
Fp-Fs = m*a
29.4*sin A - 0.46*29.4*Cos A = m*0 = 0
29.4*Sin A = 0.46*29.4*Cos A
Sin A = 0.46*Cos A
Divide both sides by Cos A:
Sin A/Cos A = 0.46
Replace Sin A/Cos A with Tan A:
Tan A = 0.46
A = 24.7 degrees Max.
