<u>Answer:</u>
- Slope = 27/11
- AB = 29.15 u
<u>Step-by-step explanation:</u>
<u>Given :- </u>
- Two points are given to us .
- The points are A(7,15) and B(18,42)
<u>To Find</u> :-
- The slope of the line .
- The length of line AB .
We can find the slope of the line passing through the points
and
as ,
- Plug in the respective values ,
<u>Hence the slope of the line is 27/11 .</u>
<u>Finding the length of AB :-</u>
- We can find the distance between them by using the Distance Formula .
<u>Hence the length of AB is 29.15 units .</u>
Answer:
The values of
so that
have vertical asymptotes are
,
,
,
,
.
Step-by-step explanation:
The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of
so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is
. Then, the vertical asymptotes associated with function cosecant are located in the values of
of the form:
, 
In other words, the values of
so that
have vertical asymptotes are
,
,
,
,
.
Answer:
y = -5
Step-by-step explanation:
see the pic for the steps . .
Given equation is y=2x+7 and 
Let's simplify the 2nd equation
before we can start graph so that calculation will be easy

multiply both sides by 2 to cancel out fractions

y=2x+7
which is exactly same as the first equatoin so graph of both will be exactly same and solution will be infinitely many solutions.
y=2x+7 has y-intercept 7 so first point will be (0,7). Slope is 2 so rise 2 unit up then 1 right and graph the new point.
The answer would be A, complementary angles must add up to 90 degrees