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pishuonlain [190]
3 years ago
15

5v2 in 3 in 1 312 in 2

Mathematics
1 answer:
Vladimir79 [104]3 years ago
4 0

Which type of question is this

You might be interested in
16 feet perimeter 5 feet long what is the width
miskamm [114]
P=2L+2W
L=Length
W=Width
P=Perimeter=16
So you have:
16=2×5+2w
Multiply 2 and 5 and get:
16=10+2w
Subtract 10 from both sides and get:
6=2w
Divide by 2 and get:
3=W
The width is 3.


8 0
3 years ago
Suppose a triangle has sides a, b, and c, and the angle opposite the side of length b is obtuse. What must be true?
anyanavicka [17]

Answer: D.a^2 + b^2 < c^2

Step-by-step explanation:

In the given figure, we have an obtuse triangle which has sides a, b, and c, and the angle opposite the side of length b is obtuse.

∵ In a triangle, the side opposite to the largest angle is largest.

Thus, the largest side in then given obtuse triangle= c

The Pythagorean inequalities theorem says that If a triangle is obtuse than the square of the largest side is greater than the sum of square of other two sides.

Therefore, we have

a^2 + b^2 < c^2

5 0
3 years ago
Please help will give brainliest
deff fn [24]

Since the sum of the probabilities of all possible outcomes must be 100%, we can deduce the following:

  • Cooking in under 20 minutes: 10%
  • Cooking between 20 and 30 minutes: 85%
  • Cooking in more than 30 minutes: 5%

In fact, the probabilities of cooking in less than 20 or more than 30 sum up to 15%, which means that the remaining outcome (i.e. cooking time between 20 and 30) must complete this probability to 15, and in fact 15+85=100.

That being said, all three answers are simply a combination of these three scenarios: let C be the cooking time, for aesthetic reasons:

P(C\geq 20) = P(20 \leq C \leq 30)+P(C\geq30) = 85\%+5\%=90\%

P(20 \leq C \leq 30) = 85\%

P(C\leq 30) = P(C\leq20)+P(20 \leq C \leq 30) = 10\%+85\%=95\%

3 0
3 years ago
The product of two consecutive odd integers is 782. What are the integers?
Alex Ar [27]

Call the smaller of the two odds = n

Call the next number in the sequence = n + 2

n*(n +2) = 782           Remove the brackets.

n^2 + 2n = 782          Subract 782 from both sides.

n^2 + 2n - 782 = 0    We are going to have to factor this.

Discussion

This problem can't be done the way it is written. The product of an odd integer with another odd integer is and odd integer. There are no exceptions to this. So you need to give a number that has two factors very near it's square root for this question to work.

For example, you could use 783, (which factors) instead of 782 .

Solve

n^2 + 2n - 783 = 0

(n + 29)(x - 27) = 0

<u>Solution One</u>

n - 27 = 0

n = 27

The two odd consecutive integers are 27 and 29.

<u>Solution Two</u>

n + 29 = 0

n = - 29

The two solution integers are -29 and - 27 Notice that - 29 is smaller than - 27.

7 0
3 years ago
Put these groups of numbers starting with the smallest 1.506, 1.06, 1.501, 1.605​
maks197457 [2]
1.06
1.501
1.506
1.605


Hope this helps
6 0
2 years ago
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