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Lyrx [107]
3 years ago
7

What would the answer be for this equation? 3a^3b^2x2a^2b^5

Mathematics
2 answers:
White raven [17]3 years ago
8 0

Answer:

6a^5b^7

Step-by-step explanation:

The applicable rule of exponents is ...

 (a^b)(a^c) = a^(b+c)

 

Wewaii [24]3 years ago
7 0

9514 1404 393

Answer:

6a^5b^7

Step-by-step explanation:

The applicable rule of exponents is ...

  (a^b)(a^c) = a^(b+c)

__

It looks like you want to simplify ...

  3a^3b^2\times 2a^2b^5=(3\cdot2)a^{3+2}b^{2+5}=\boxed{6a^5b^7}

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JK in the coordinate plane has endpoints with coordinates (-4, 11) and (8,
atroni [7]

Answer:

(0, 7)

Step-by-step explanation:

Given:

J(-4, 11)

K(8, -1)

JP:JK = 1/3

Required:

Coordinates of P

SOLUTION:

Use the formula, (x, y) = (x_1 + k(x_2 - x_1), y_1 + k(y_2 - y_1)) to find the coordinates of point P, that partition the segment JK into the ratio 1/3.

Let,

J(-4, 11) = (x_1, y_1)

K(8, -1) = (x_2, y_2)

k = \frac{1}{3}

Thus, plug in the values as follows:

P(x, y) = (-4 + \frac{1}{3}(8 -(-4)), 11 + \frac{1}{3}(-1 - 11)

P(x, y) = (-4 + \frac{1}{3}(12), 11 + \frac{1}{3}(-12)

P(x, y) = (-4 + \frac{12}{3}, 11 + \frac{-12}{3})

P(x, y) = (-4 + 4,  11 + (-4)

P(x, y) = (0, 7)

The coordinates of point P, are (0, 7)

3 0
3 years ago
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2 years ago
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Kitty [74]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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How to find the point that is equidistant from (5,-5) and (1,1)
Lina20 [59]

Answer:

(3, -2)

Step-by-step explanation:

The <em>midpoint</em> of two points is half-way between the x-values and the y-values.

The formula is

M = ((x₁ + x₂)/2, (y₁ + y₂)/2)

For the points (5,-5) and (1,1),

Half way between the x values is

(x₁ + x₂)/2 = (5 + 1) /2 =  6/2 =  3

Half way between the y values is

(y₁ + y₂)/2= (-5 + 1)/2  = -4/2 = -2

M = (3, -2)

The graph below shows your two points at (5,-5) and (1,1) and the mid-point at (3, -2).

3 0
3 years ago
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7nadin3 [17]

Answer:

hope it helped

Step-by-step explanation:

A+w=p

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