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topjm [15]
2 years ago
6

Zoe says an equilateral triangle is always an acute triangle, but an acute triangle is never an equilateral triangle. Which stat

ement explains whether Zoe is correct or not?
A. Zoe is not correct because equilateral triangles are acute triangles with three sides of equal length. Acute triangles can sometimes be equilateral triangles.

B. Zoe is not correct because equilateral triangles have three acute angles. Acute
triangles have three acute angles, so acute triangles are always equilateral triangles.

C. Zoe is correct because equilateral triangles have three sides of equal length, and acute triangles have three sides of different lengths.

D. Zoe is correct because equilateral triangles have three acute angles. Acute triangles have one acute angle, so an acute triangle cannot be an equilateral triangle.

HELP!
Mathematics
1 answer:
miv72 [106K]2 years ago
7 0

Answer:

Step-by-step explanation:

Discussion

She is correct.

An equilateral triangle is a specific acute triangle. An acute triangle can never be an equilateral triangle because it has 3 unequal angles. Your best choice is likely C, but none of the choices are first rate choices.

Answer: C

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If 2 &gt; -a, then _____.<br><br> a &gt; 2<br> a &gt; -2<br> a &lt; 2<br> a &lt; -2
FinnZ [79.3K]

Answer:

B. a >-2

Step-by-step explanation:

Hope this helps! Ask me anything if you have any quistions!

4 0
3 years ago
Read 2 more answers
PLEASE HELP...AGAIN this is due tomorrow and it's late at noon..
dimaraw [331]
What do you need help with and what subject
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3 years ago
2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of
IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., \mu = 35 and \sigma = 6. We know that the probability density function for a normal distribution with a mean of \mu and a standard deviation of \sigma is given by

f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]

in this case we have

f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]

Let X be the random variable that represents a row score, we find the values we are seeking in the following way

a)  we are looking for a number x_{0} such that

P(X\leq x_{0}) = \int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65, this number is x_{0}=37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number  x_{1} such that

P(X\leq x_{1}) = \int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9, this number is x_{1}=42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

P(28\leq X\leq 38)=\int\limits^{38}_{28} {f(x)} \, dx = 0.57

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

P(41\leq X\leq 44)=\int\limits^{44}_{41} {f(x)} \, dx = 0.09

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

6 0
3 years ago
Read 2 more answers
Number four please help. Whatever helps gets a Brainly award
pashok25 [27]
29.99 + 35.00 + 3.25 + 3.25 = 71.49

125.00 - 71.49 = 53.51

53.51 ÷ 22.50 = 2.4 = 2

She can buy 2 pairs of shoes.

Hope this helps!!
~Kiwi
8 0
3 years ago
Can someone do this for me ahhhh
Aleksandr [31]
28:13 is the answer i’m pretty for sure
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