Answer:
The enrollment after 5 years is 10,724
Step-by-step explanation:
Generally, we can have the depreciation formula written as follows;
A = P(1 - r)^t
A is the number of enrollment in after a certain number of years t
P is the initial population which is 13,500
r is the rate of depreciation which is 4.5% = 4.5/100 = 0.045
t = 5 years
Substituting these values, we have it that;
A = 13,500(1-0.045)^5
A = 10,723.84
Answer:
C. x=2
Step-by-step explanation:
-3(x-4)=2x+4-x
-3x+12=x+4
+3x +3x
-----------------------
12=4x+4
-4 -4
-----------------------
8=4x
-- ---
4 4
-----------------------
x=2
The range is 13 because 115-102 is 13
Answer:
357
Step-by-step explanation:
A) We replace x = - 5 and u = 3 into -3x^3 -2y^2
and we have -3x^3 -2y^2= -3*(-5)^3 -2*3^2= -3*(-125)- 2*9
or -3x^3 -2y^2 = 375-18= 357
The answer is 357.
B) Replace h = -2 into h^2-3h+2
we have h^2-3h+2 = (-2)^2 -3*(-2) +2 = 4 +6 + 2= 12
The answer is 12
Have a good day.
Answer:
40.50 is correct answer according to me
