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3 years ago

Grapes coast 1.99 per pound. write an expression for the coast of grapes

Mathematics

1 answer:

ELEN [110]3 years ago

3 0

1.99p = x

x = total cost

1.99p = 1.99 per pound of grapes.

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Rewrite 9.524 as a mixed number in lowest terms

Anit [1.1K]

Answer: 9 132

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250

9.524 = 9 + 0.524 = 9 + 524 = 9 524 = 9 524:2 = 9 262 = 9 134

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1000 1000 1000:2 500 250

8 0

3 years ago

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Theres a picture help please!!!

Goryan [66]

The correct answer is A

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3 years ago

A car dealership has SUVs and sedans in a ration of 5:9. How many sedans does the car dealership have if there are 140 SUVs

Elza [17]

To solve this, all you need to do is compare the ratio to the amount of SUVS there are.

5/9 (SUVs to sedans)

140/? (SUVs to sedans)

140 ÷ 5 = 28

9 x 28 = 252

140/252

There are 252 sedans in the car dealership! :D

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2 years ago

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Elsa makes a poster that is 1.5 m tall. Greg makes a poster that is 96 cm tall. Who makes a taller poster?

Mademuasel [1]

Answer:

dont mind me just grinding for points

Step-by-step explanation:

6 0

1 year ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

2 years ago