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2 years ago

Ugdhcuhevshdirnebdbbdnf

Mathematics

2 answers:

Evgen [1.6K]2 years ago

5 0

Answer:

D (2,0), (3,0)

Step-by-step explanation:

Sorry if it's wrong

zheka24 [161]2 years ago

4 0

Answer:

(2,0)(4,2)

Step-by-step explanation:

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What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

2 years ago

What is the 11th term of the sequence: 7, 13, 19, 25, ....

wel

pattern is adding 6

so the 11th would be 67

8 0

2 years ago

Read 2 more answers

If y = 2 and x = 5, Then solve<br> 3x + 4 + 2y<br> A 20<br> B 61<br> C 23<br> D 0

Arisa [49]

Answer:

Step-by-step explanation:

8 0

2 years ago

Trig. help. How does <img src="https://tex.z-dn.net/?f=2sin%20%28%5Cfrac%7B1%7D%7B2%7D%20x%29cos%28%20%5Cfrac%7B1%7D%7B2%7D%20x%

kotegsom [21]

Recall that 2sin(x) cos(x) is actually equal to sin(2x).

We can prove this by expanding sin(2x) to sin(x + x).
sin(x + x) = sin(x) cos(x) + cos(x) sin(x) = 2sinxcosx

Thus, 2sin(x/2)cos(x/2) can be rewritten in the form:
sin(2x/2), and this simplifies down to sinx.

5 0

2 years ago

After *triangle* ACE is dilated by a factor of 5, It has an area of 100 square inches. What was its area before dilation?

Anarel [89]

<h3>Answer: 4 square inches</h3>

Explanation:

Square the linear scale factor to get 5^2 = 25

This means that,

new area = 25*(old area)

We take this idea in reverse to find the old area

old area = (new area)/25

old area = (100 sq inches)/25

old area = 4 square inches

6 0

1 year ago