Answer:
![\large\boxed{4\sqrt[3]{64}=16}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B4%5Csqrt%5B3%5D%7B64%7D%3D16%7D)
Step-by-step explanation:
![\sqrt[3]{a}=b\iff b^3=a\\\\4\sqrt[3]{64}=(4)(4)=16\\\\\sqrt[3]{64}=4\ \text{because}\ 4^3=64](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%7D%3Db%5Ciff%20b%5E3%3Da%5C%5C%5C%5C4%5Csqrt%5B3%5D%7B64%7D%3D%284%29%284%29%3D16%5C%5C%5C%5C%5Csqrt%5B3%5D%7B64%7D%3D4%5C%20%5Ctext%7Bbecause%7D%5C%204%5E3%3D64)
Answer:
x=1/5y-2
Step-by-step explanation:
Step 1: Flip the equation
5x+10=y
Step 2: Add -10 to both sides
5x+10+-10=y+-10
5x=y-10
Step 3: Divide both sides by 5.
5x/5 =y-10/5
x=1/5y-2
Answer:
B. 7.9 in^2
Step-by-step explanation:
Part I.
Finding the fraction of the circle that is the sector
To start, let’s find the fraction of the circle that the sector covers. Since the measure of the central angle is 36, we get 36/360 or 1/10 of the circle.
Part II.
Finding the area of the Circle
The area of a circle is pi*r^2. Since r=5, then the area is 25pi.
Part III.
Finding the area of the sector.
Since the sector is 1/10 of the circle, its area is 1/10 of the circle’s area. So the area of the sector is 25/10*pi or (5/2)pi. This is approximately 7.9 in^2.
Sorry for my previous answer; I didn't read that it was point slope form ;-;
y - 7 = 9(x - 2)
9x - y - 11
I believe this is the answer, let me know if I'm incorrect :)
Answer
26.5
Step-by-step explanation
I think, I’m not sure because it seems so simple.
