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2 years ago

Is this Network a HAMILTONIAN Circuit? If so write the path.

Mathematics

1 answer:

Anton [14]2 years ago

6 0

The path of the given Hamiltonian diagram is A, E, B, C, D, F. See explanation below.

<h3>What is a Hamiltonian Path?</h3>

A Hamiltonian path, also known as a traceable path, is one that visits each vertex of the graph precisely once.

A traceable graph is one that contains a Hamiltonian path.

Hence, the path is given as;
A, E, B, C, D, F

Learn more about Hamiltonian Paths at;
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Use the domain {-1, 0, 1, 2, 3} and plot the points on the graph that would best satisfy the equation. The bold grid marks repre

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3 years ago

How to solve this? Don't just give me the answer help me learn this.

Sphinxa [80]

Answer:

I'm not entirely sure but I think that what is says is that it wants you to find the value of x in (4x+28) to make it 116 degrees because it is that same angle. So what you do is you get (4x+28)=116 and you do this because they are the same angle so you use 116 and get it to solve x. Since I'm lazy, then I go to this website and type the equation in: m a t h w a y . c o m but without all of the spaces, I had to do that so it would let me answer this, but I'll do it the real way this time. (4x+28)=116 Their is a rule in math that as long as you do something to one side of the equal sign in the equation, you have to do it to the other and it will still work. So, you minus 28 from both sides so that you can get rid of it and you now have 4x=88. Now you should know this part but you divide 4 from both sides to make so x is alone. Now you have x=22 because you divided 4 from each side. So their is your answer: x=22.

Step-by-step explanation: If you have the answer key that you can check from to make sure you got it right because I know some teachers let you do that, then you should make sure that is right, but I am pretty sure it is.

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3 years ago

Combine like terms to create an equivalent expression<br> 3x²+5y²-x^2+2y^2-4

Alja [10]

Answer

3x²+5y²-x^2+2y^2-4

2x^2+7y^2-4

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3 years ago

A divided by 9= -4 plss solve

iragen [17]

Answer:

<h3> $\boxed{ \bold{ \sf{ \huge{ \boxed{ a = - 36}}}}}$ </h3>

Step-by-step explanation:

$\sf{ \frac{a}{9} = - 4}$

Apply cross product property

⇒ $\sf{a = - 4 \times 9}$

Multiply the numbers

⇒ $\sf{a = - 36}$

Hope I helped!

Best regards!!

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3 years ago

Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o

Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is $\hat p_1$ = 1020/1272 = 85/106 = $0.8\overline {0188679245283}$ ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is $\hat p_2$ = 5343/6238 ≈ 0.8565

c) We have the following two way table;

$\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}$

$The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780$

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

$95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}$

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

$95 \% \ CI \approx 0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155$

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

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3 years ago