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lapo4ka [179]
2 years ago
6

Suppose in a class of 60 students 5 have no siblings, 26 have one sibling, 14 have two siblings, and 15 have three siblings. Cal

culate the relative frequency of students who have three siblings. (please express as a percentage)
Mathematics
1 answer:
Otrada [13]2 years ago
5 0

The relative frequency of students who have three siblings is 25% given that there are 60 students in a class in which 5 have no siblings, 26 have one sibling, 14 have two siblings and 15 have three siblings. This can be obtained by using the formula for relative frequency.

<h3>What is the relative frequency of students who have three siblings?</h3>

Given that,

total number of students in the class = 60

number of students who have no sibling = 5

number of students who have 1 sibling = 26

number of students who have 2 sibling = 14

number of students who have 3 sibling = 15

Formula for relative frequency = f/n, where f is the number of times the data occurred, n is the total number of frequencies.

Therefore,

relative frequency of students who have three siblings = 15/60 = 0.25

In percentage ⇒ 0.25 × 100 = 25%

Hence the relative frequency of students who have three siblings is 25% given that there are 60 students in a class in which 5 have no siblings, 26 have one sibling, 14 have two siblings and 15 have three siblings.

Learn more about relative frequency here:

brainly.com/question/16832475

#SPJ4

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Please answer with explanation
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Answer:

(a)- 2 [ ( - \frac { 1 } { 4 } ) - 12 ( - 1 ) ^ { 2 } ] - 5 [ 24 + 2 ( - 12 ) ] ^ { 2 }−2[(−

4

1

)−12(−1)

2

]−5[24+2(−12)]

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-2\left(-\frac{1}{4}-12\right)-5\left(24+2\left(-12\right)\right)^{2}−2(−

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Subtract 1212 from -\frac{1}{4}−

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-2\left(-\frac{49}{4}\right)-5\left(24+2\left(-12\right)\right)^{2}−2(−

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\frac{49}{2}-5\times 0^{2}

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49

to get \frac{49}{2}

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49

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\frac{49}{2}

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49

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2

b

2

−3a

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b

2

a=−

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Step-by-step explanation:

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