Given :
A 2450 kg stunt airplane accelerates from 120 m/s to 162 m/s in 2.10 s.
If the airplane is putting out an average force of .
To Find :
The average friction force exerted on the airplane by the air.
Solution :
Acceleration is given by :
Now, force equation is given by :
Therefore, frictional force exerted in the airplane by the air is 9810 N.
Answer:
<em>t=14.96 sec</em>
Explanation:
<u>Diagonal Launch
</u>
It's a physical event that happens where an object is thrown in free air (no friction) forming an angle with the horizontal reference. The object then describes a path called a parabola.
The object will reach its maximum height and then return to the height from which it was launched. The equation for the height is
:
Where vo is the initial speed, is the angle, t is the time and g is the acceleration of gravity
.
In this problem we'll assume the arrow was launched from the ground level (won't consider the archer's height). Thus , and:
The value of y is zero twice: when t=0 (at launching time) and in t= when it goes back to the ground. We need to find that time by making
Dividing by
Then we find the total flight time as
Atomic mass = number of protons + number of neutrons = 4+5 = 9 amu