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Dennis_Churaev [7]
3 years ago
9

When a wave passes from one medium to another, its _________ remains constant.

Physics
1 answer:
Mashcka [7]3 years ago
3 0
The frequency will not change
You might be interested in
The Sears Tower vibrates back and forth, it makes about 8.6
Leni [432]

Answer: Frequency is 0.143 Hz; Period is 7 seconds

Explanation:

Number of vibrations = 8.6

Time required = 60 seconds

Period (T) = ?

Frequency of the vibrations (F) = ?

A) Recall that frequency is the number of vibrations that the Sears tower completes in one second.

i.e Frequency = (Number of vibrations / time taken)

F = 8.6/60 = 0.143Hz

B) Period, T is inversely proportional to frequency. i.e Period = 1/Frequency

T = 1/0.143Hz

T = 7 seconds

Thus, the frequency and period of the vibrations of the Sears Tower are 0.143 Hz

and 7 seconds respectively.

7 0
4 years ago
Not so fast! If a force of 2500 N is used over
Masteriza [31]

Answer:

B 1500N

Explanation:

The acceleration of the car - at least the average one, but that will do, is a= \frac{\Delta v}{\Delta t} = \frac 53 ms^{-2} = 1.66 ms^{-2}

We know the acceleration, we know the force, let's drop them in Newton second law.

F= ma = 2500= m \frac53 \rightarrow m=500\times 3 N = 1500N

3 0
3 years ago
What are the very small participes that make up all matter
Semenov [28]

<u>Answer</u> :

atom

<u>E</u><u>xplaination</u> :

You cannot see the fundamental particles that makes up matter.

Yet, ll matter os composed of such particle called atoms.

atoms - the smallest particle of an element that retains its identity in a chemical reaction.

<em>pls mark as brainliest...</em>

6 0
4 years ago
muatan sebesar 1.200coloumb mengalir melalui sebuah penghantar selama 10 menit.hitung besar arus listrik yang mengalir melalui p
lidiya [134]
Can you put this in english plz i dont want to be rude but i cant read this at all
3 0
4 years ago
A parallel-plate air capacitor is made from two plates 0.200{\rm m} square, spaced 0.800 {\rm cm} apart. It is connected to a 12
Phoenix [80]

Answer:

A)  C = 4.425 10⁻¹³ F,  B) Q = 6.31 10⁻¹¹ C,  C)  E = 8.9 10⁴ N / C,  

D)  u_{E} = 3.19 10⁻⁹ J

Explanation:

Part A. Capacitance is

           C = ε₀ A / d

in this case distance is d = 0.800 cm = 0.800 10⁻² m and the area of ​​the plates is x = 0.200 cm= 0.2 10⁻² m, all the quantities must be in the SI system for the result to be in Farads

           A = x²

           A = (0.2 10⁻²)²

           A = 4 10⁻⁶ m

let's calculate

          C = 8.85 10⁻¹² 4 10⁻⁶ / 0.8 10⁻²

          C = 44.25 10⁻¹⁴ F

          C = 4.425 10⁻¹³ F

Part B. The charge on each plate is

          Q = C ΔV

           Q = 4.425 10⁻¹³ 120

           Q = 6.31 10⁻¹¹ C

Part C. the electric field of a plate is

           E = σ / 2ε₀

where the charge density is

            σ = Q / A

we substitute

             E =\frac{Q}{ 2\epsilon_o A}

       

let's calculate

             E = \frac{6.31^{-11} }{ 2 \ 8.85^{-12} \ 4^{-6} }

             E = 8.9 10⁴ N / C

Part D. stored energy

              u_{E} = ½ C V²

               u_{E} = ½ 4.425 10⁻¹³ 120²

               u_{E} = 3.19 10⁻⁹ J

7 0
3 years ago
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