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Tema [17]
3 years ago
13

One disadvantage of using proprietary licensed software is that

Physics
2 answers:
Gnesinka [82]3 years ago
7 0

Answer:

b- the software company may decide to discontinue support for the product.

Explanation:

right on E2020

Vaselesa [24]3 years ago
5 0

Answer:

its b

Explanation:

You might be interested in
What are the differences and the similarities between psychology and the social science
tiny-mole [99]

Answer:

psychology has to do with the mind and brain while social science has to do with the scientific study if human relationships

3 0
3 years ago
In Lesson 20, a magnesium strip was used to ignite the thermite reaction. When magnesium is placed in a flame from a small blow
nadezda [96]

Answer:

2 electrons will be needed by unbound oxygen in order to fill its 2nd shell.

Explanation:

The chemical reaction between magnesium and oxygen gives magnesium oxide as a product.The reaction is chemically represented as:

2Mg(s)+O_2(g)\rightarrow 2MgO(s)

Magnesium is a metal of group-2 with 2 valence electrons.It has atomic number of 12.

[Mg]=1s^22s^22p^63s^2

In order to attain noble gas configuration it will loose two electrons.

[Mg]^{2+}=1s^22s^22p^6

Mg\rightarrow Mg^{2+}+2e^-...[1]

Oxygen is a non metal of group-16 with 6 valence electrons..It has atomic number of 8.

[O]=1s^22s^22p^4

In order to attain noble gas configuration it will gain two electrons.

[O]^{2-}=1s^22s^22p^6

O+2e^-\rightarrow O^{2-}..[2]

2 electrons will be needed by unbound oxygen in order to fill its 2nd shell.

6 0
3 years ago
The y-component of the force F which a person exerts on the handle of the box wrench is known to be 86 lb. Determine the x-compo
emmainna [20.7K]

Answer:

x-component of force is  38.18 lb where as magnitude of Force is 93.16

Explanation:

Fy of the force F exerted on the handle of the box wrench = 86 lb

Considering the triangle in Fig 1

magnitude of perpendicular = P =  12

magnitude of base = B = 5

using Pythagoras theorem

                        H= \sqrt{P^{2} + B^{2}}

                 H= \sqrt{12^{2} + 5^{2}}

            H=13\\\implies cos \theta = \frac{5}{13} \\\implies sin \theta = \frac{12}{13}\\

y-component of force is given given as:

                              86 = Fsin\theta\\F = 86 (\frac{13}{12})\\F = 93.16 lb\\F_{x} =F cos \theta\\F_{x} = 93.16 (\frac{5}{13})\\F_{x} =38.18 lb.

5 0
3 years ago
Interactive Solution 9.1 presents a model for solving this problem. The wheel of a car has a radius of 0.300 m. The engine of th
Murrr4er [49]

Answer:

740 N

Explanation:

We are given that

Radius,r=0.3 m

Torque,\tau=222 Nm

We have to find the magnitude of the static frictional force.

According to question

Torque by engine=Torque by static friction

222=f\times r

f=\frac{222}{r}

f=\frac{222}{0.3}

f=740 N

Hence, the magnitude of static frictional force=740 N

8 0
3 years ago
An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only
alexira [117]

Answer:

The answer is "2.352 \ \frac{m}{s}"

Explanation:

\to mass(m_1)=102 \ kg\\\\\to  mass(m_2)=10 \ kg \\\\\to v=2.10\ \frac{m}{s}\\\\

momentum before:

\to p=(m_1+m_2)v

       =(102+10)2.10\\\\=(102\times 2.10 +10 \times 2.10)\\\\=214.2+21\\\\=235.2

momentum After:

\to p=(m_1+m_2)v

       =(102\times 0 +10 \times v)\\\\ =(0 +10v)\\\\=10v\\

Calculating the conservation of momentum:

\to \text{momentum before = momentum After}

\to 235.2=10v\\\\\to v= \frac{235.2}{10}\\\\ \to v=2.352 \ \frac{m}{s}

3 0
2 years ago
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