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TEA [102]
3 years ago
9

If an object force of 50 N is used to move an object a distance of 20 m, what distance must the object be moved if the input for

ce is 10 N, so that work in = work out?
Physics
1 answer:
steposvetlana [31]3 years ago
5 0

Answer:

\ d_{out} = 100 \ m.

Explanation:

Given data:

F_{in} = 50 \ \rm N

F_{out} = 10 \ \rm N

d_{in} = 20 \ m

Let the distance traveled by the object in the second case be d_{out}.

In the given problem, work done by the forces are same in both the cases.

Thus,

W_{in} = W_{out}

F_{in}.d_{in} = F_{out}.d_{out}

\Rightarrow \ d_{out} = \frac{F_{in}.d_{in}}{F_{out}}

\ d_{out} = \frac{50 \times 20}{10}

\ d_{out} = 100 \ m.

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Answer:

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Explanation:

Kinetic energy of electron, K = 1.6 x 10^-17 J

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Let the potential difference is V and the electric field is E.

(a) The relation between the kinetic energy and the potential difference is

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V = 100 V

The relation between the electric field and the potential difference is given by

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(b) The force acting on the electron, F = q E

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So, F = -e x E

It means the direction of electric field and the force are both opposite to each other.

The direction of electric field and the force on electron is shown in the diagram.

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Answer:

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